Question

FOR M A 12, Based on your knowledge of the periodic table and formulas for compounds, which of the following balanced equations is correct? a) Lig (s)+ F (g)Li,F (s) d) 2Li (s) +F2 (g)2LIF (s) b) Li (s)+ F ()LiF, (s) e) 4Li (s)+2F, (a)2LiF (s) c) Li (s)+F (g) LiF (s) 13. When the equation CH +O,CO; + H,O is balanced with the smallest whole number coefficients, it will have a a) 10: H,O in front of (Fill in the blanks with a number, then a formula) d) 5:CH b) 7: H2O c) 11:O e) 8: CO For questions 14 and 15 consider the following balanced equation: 2 NaCIO, 2 NaCl+30 14. 3 moles of NACIO, will produce how many moles of O, ? b) 1.5 a) 4.0 c) 0.67 d) 2.0 e) 4.5 15. How many grams of NaCIO, must decompose to yield 48.0 g of oxygen? e) 53.3 g a) 106.5 g b) 159.8 g d) 213.0 g c) 71.4 g 16. A solution is prepared by mixing 42.0 g of sodium sulfate with 139 g of water. What is truo? a) There will be 181 g of solution. c) There will be exactly 181 mL of solution e) a and d b) m/m% sodium sulfate is 42.0 % d) the m/m % water is 76.8% 17. 15.85 g of SrCl2 are added to a container, and a solution is made by adding water to the 200.0-mL mark. The molarity of this solution is b) 0.500M a) 0.100 M d) 0.078M c) 15.6M e) 2.00M 18. How would you prepare 250. mL of a 4.50 v/v % alcohol in water solution? a) add 4.50 mL of alcohol to 250 mL of water e) add 11.25 mL of alcohol lo a container; then add water to the 250-mL mark d) add 4.50 mL of alcohol to a container; then add 245.5 mL of water e) add 11.25 mL of alcohol to a container; then add 238.75 mL of water b) add 11.25 mL of alcohol to 250 mL of water 19. 55.0 mL of water are added to 300. mL of a 3.50 M solution of NaCL Assume the volumes are additive. The molarity is now b) 1.05M d) 2.96M e) 0.00986M a) 3.50M c) 0.0296M 20. A beaker contains 200. mL of a 2.00M solution of potassium bromide. If you want to double the molarity, you could a) add 200 more mL of 2.00M potassium bromide solution b) pour out half of the solution c) evaporate water until only 100 mL of solution remain. d) add two moles of potassium bromide e) all of the above
do numbers 12 through 20

Answer 1

THANK YOU VERY MUCH
molar man of Nacioz 023+35.5+16* 3 = 106.5 MTOTT 2li cw +f2 (9) 2 Lif cs) C7H16 to 7CO2 + 84₂0 JL 02 C 1102 a Nacioz 2 mole → 2Nach + 302 - 3 mole Imole Nacio, I mole " Now 3 moles Nacio And 4.5 Produce = 3mole O₂ " 3 mole 02 Produce = 3 x 3 mole O₂ - 4.5 mole O₂ 15 - & Nacro a Nace +30₂ 2mol 3 mole (2x 106.5) 6 x 16 = 96 Groom 23 gram 96 gram oxygen Produced byo = 23. g Nacioz I gram Oxygen Produced by = 213 Nacioz Now 48 grom Oxygen 213 X 48 Nacloz = 106.5 gram Nadog Ans (9) 106.5 PAGE

DATE molar man of Silly - 158. 53 ghrof. DATE T O 16. 42 gram Na, so 4 + 139 gram 420 o mass of solution - 181 gram. m/m 4. of H2O = 139 X100 = 76:8). 101 Anic - 64 Na,sex = 2 x100 = 23 : /. (a) and (d) A mass of Silla /molar mass of Sv C/2. - 1 molarity = volume in a WE 15. 85 grom /158.53 g/mol 200/1000 L = 0.500M 15.85 x 1000 200 x 158.53 Ans (6) 18) X 100 %. Of Alcohol = volume of Alcohol totul volume VAlcohol -X100 - some = 11.25 ml Alcohol 4.50x250 100 4.50 = 11.25 ml Alcohol +238.75 ml 40 = 250 ml Solution los (e) PAGE 1

300 55 DATE DATE TUTTI Miv = M₂ V₂ (molarity equation m = 3.50 m₂ = ? v = 3oome = 300ml +55.ome T = 355 me 3.0 x 30o = M₂ x 355 I m = 3.50 X 300 = 2.96 355 Ans (d) 2.96M 20. m = 2.00M V = 200 ml M = double of mi m₂ = ax 2 = 4 m ₂ = ? I mv = M2 V2 2 x 200 = 4 x V₂ 400 v = 2X200 100 V2 = 2X200 4 - molarity become V2 = 100 ml when f at 100 me = double evaporate 120 unlil only remain And 100 ml Solution thank you very much PAGE