Question

c) 5 in front of O 15. Consider the balanced equation: 2 excess oxygen, then which of the follow e equation: 2S (s) + 30. () >> 250, Ir 64.29 of sulfur are reacted with which of the following will be true? The amount of So, that for will 0.1gb) 40.0 B ) 160.23d) 22.49 €) 52B 16.200 mL of a 15.0% v/v alcohol in water 15.0% V/v alcohol in water solution would contain how many ml. of alcohol a) 15.0 mL b ) 150 ml 100 ml. d) 20.0 ml e) 13.3 m 17. 200.0 ml of a sodium chloride is wat ca solution contains 58.5 g of NaCl. What is its molarity? V y h a) 1.00 M b ) 5.00 M e ) 58.5 M a) 3.42 M e ) 0.293 M a 18.250.0 mL of a 10.0% m/v solution of Na,PO, are mixed with 50.0 mL of water. (Assume the final volume is 300.0 L The m/v % is now a) 8.33% (b) 3.00% c) 5.00% d) 12.0% e) still 10.0% since no sodium phosphate was added 1952.0 g of sucrose (C2H20.1. molar mass - 342 g/mol) are mixed with 48.0 g of water. The density of this solution is 1.24 g/mL. Which of the following is true? The moles of sucrose in the solution is 0.152 by The volume of the solution is 80.6 mL The m/m % of the sucrose solution is 52.0% d) The molarity of the solution is 1.89 M c) all of the above 400 g of a 6,00% m/m glucose in water solution sits in a beaker. Exactly half of the solution is dured down the drain. What is true about the solution that remains in the beaker? a) It contains half the original mass of glucose. b) It contains half the original number of molecules of glucose. c) It is now a 3.00% m/m solution of glucose in water. d) a and b eya, b, and c
do numbers 15,16,17,18,19,20 please

Answer 1

SopM-15 2 SO3) 2 Ses301 g) anouut 03 jom Ct ven mas To tind Malar masJ G4.2 8 2.665 2 moles 2S03 cg) 2 SestS0,g) 2moles Finealy 303 2x molas mas s Mass dS03 2x80. 0.2 160.29 t0 phouduced Hance, Amut Solu.-16 200mL a 159. V/,atcouol in water souhion soluton mL alcuhol. To jindHow volume solute Xlo Vo me soluhon Voune alcohol 2 oo mL alcoho=3o ml olume Heuce Hhe ouhon 30 mL dalcohol preseut tn

toduu m chlon'de in water contauns Mol Solume toution (L) Molarity Volume mol molanity 5 M 5M. Molarih Nqu Hen Sol 25 o .0 soluh'on mxed tuin w ater nas o o ute loo Vo ume solutian Mass o olute 2 5o Mai o 6ute= 25 Anal votu coluhou 2r0 +5 3 oD A.33% Hauce 8.33%

Sol-19 342j/) malar ma «СGHe0ns wates u8.0 mixed wjt re the's Jouhon is Dansity f 2 gut nose mo La 3 42 0.152 To tal mass olah'on 527 4 8 nass De si ty Volune mass Vo lune De m L 24 2 oT 2 tho Solut'on Me lanity 0о.6 X10 3 89M сьмесt. ophion Ce) Mau e

og .o . M/m cIe in water solubion Solub'o poused drun o20 Hal of the soluton New mai lnihally mass ofSolute Mass of soluteon mors gucose » ha New mass 2 Lwhaliy moles X NA Molo cele ocoe x NA M 12 A NA irally nuole cules ourcete alio naduced to e elf coMhe ot opfion So