Solution-
The balanced chemical equation can be written as:
2 KCl + Pb(NO3)2 ====> 2 KNO3 + PbCl2
Also
M(KCl)= 1.50 M
M(Pb(NO3)2)=2.00 M
V(KCl)=50 mL
Now from the balanced reaction:
1* number of mol of KCl = 2*number of mol of Pb(NO3)2
=>1*M(KCl)*V(KCl) =2*M(Pb(NO3)2)*V(Pb(NO3)2)
=>1*1.50 M *50 mL = 2*2.00M *V(Pb(NO3)2)
=>V(Pb(NO3)2) = 18.75 mL
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