Balanced chemical equation is:
2 KCl + Pb(NO3)2 ---> 2 KNO3 + PbCl2
Here:
M(KCl)=0.322 M
M(Pb(NO3)2)=0.246 M
V(KCl)=36.0 mL
According to balanced reaction:
1*number of mol of KCl =2*number of mol of Pb(NO3)2
1*M(KCl)*V(KCl) =2*M(Pb(NO3)2)*V(Pb(NO3)2)
1*0.322 M *36.0 mL = 2*0.246M *V(Pb(NO3)2)
V(Pb(NO3)2) = 23.6 mL
Answer: 23.6 mL
Part A How many mL of 0.246 M Pb(NO3)2 are needed to react with 36.0 mL...
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