Question

Im not following the math here, can someone please help clarify?

хто 1 I 0,20 0.no 17) The equilibrium constant, Kc, for the reaction Ĉ C -x -x PC13(g) + Cl2(g) = PC15(g) is 49 at 230°C. E 0.70-K 0.70-X If 0.70 mol of PC13 is added to 0.70 mol of Cl2 in a 1.00-L reaction vessel at 230°C, what is the concentration of PC13 when equilibrium has been established? 0.70-Ki A) 0.59 M B ) 0.83 M C) 0.35 M BR0.11M E) 0.049 M K Cpels] = x > X = 1,42+ (1.42²-4416, 491) Ž he CPCP3][cz] 10.70*12 =(1.42 + 0 12 37) 12 = 81826 EPols] =0.70-156=0,11 Nos Potusice X-=11142-02237)/2 = 0.54 2.

Answer 1

o Pelz (8) + 618) - Pel (8), Ke 298 atto 0.7 0.7 bet till equilibrium & mole of pels es formed alt team 0.7 x 0.7.x x. at eaim. [ch] [143] = 0.7-1 - (0.7-x) m. [Pus] x = xm. Ко - СРЧ, [Pcly] [₂] 49 - x (7-^)(-7-x) 49 (-7-x)= x 49(-72+x21. w p 24.01 +49x² - 68.6x2x a la 4922-696% +29.01=0 x, 20.83, X₂=0.59.00 so we no reject x because this gives negative concentration of [cly] & [Pelz]. : [[PusJegim = 0.50 m