Question

Math toolbox: ax2+bx+c =0 solve x= -bb2 - 4ac 2a 1 cm3 = 0.001 dm3 The equilibrium constant is calculated Keq = 0.36 for the reaction @ 400 K when using M (mol/dm3) as the unit for the gasses. note: not the pressure unit. PC15 (g) <=> PC13 (g) + Cl2 (g) When using M as the units, the Keq is unitless with unit canceled to c = 1 M. Giving that 5.172 g of PC15 (Mw = 208 g/mol) was initially placed in a reaction vessel of volume V = 250 cm3 When reach equilibrium, determine the molar concentrations of PCl3 in the mixture assuming ideal gasses for all. concentration of PCI3 = M. 3 sig. fig.

Answer 1

Mole = weight/molar mass

Concentration= mole/volume

Keq is equilibrium constant which is written as ration of product of concetration of product to the product of concetration of Reactant.

1 litre= 1dm^3

Solve quadratic equation using given formula to find out value of x.

Equilibrieem constant Reg = 0.36 weight of P45 = 5.172 g mole of pus = 5.172 0.0249 208 Volume = 250cm3 3 } Volume = 0.2500m 1 cm3 = 0.000 dm3 = 0.2502 i concentration 0.0249 of U5 = 0.1 0.350 ( لعنت ( pus Puz + (9) ch (9) initial Equilibrium 0.)-X X. Req CP Ch] [ch] [pus) - 0.1-2 0:36 = 2² 0.- 1036-0, 3676 = x2 => x2 +0.36%-0.036 =0 using math toolbox formula : -0.36 + 10.1296+ 0.144 X २ x = 0.0815 Molwr concentration of pl = x = 0.0815 M Ang CS Scanned with CamScanner