Question

Math toolbox: -b+ b2 - 4ac ax2+bx+c =0 solve x= 2a 1 cm3 = 0.001 dm3 The equilibrium constant is calculated Keq = 0.36 for the reaction @ 400 K when using M (mol/dm3) as the unit for the gasses. note: not the pressure unit. PCL5 (g) <=> PC13 (g) + Cl2 (g) When using M as the units, the Keq is unitless with unit canceled to C@= 1 M. Giving that 4.733 g of PC15 (Mw = 208 g/mol) was initially placed in a reaction vessel of volume V = 250 cm3. When reach equilibrium, determine the molar concentrations of PC13 in the mixture assuming ideal gasses for all. concentration of PCI3 = M. 3 sig. fig.

Answer 1

Mass of Pels - 4.733 from molar mass = 208 goolmat mole (Pols) = 0.02275 mole 80 Molarity 0.02275 mole 0.0 91 M 250cm X IL 1000cm 80; Pas pek & ch Initial 0.091M change te tx Ateq. (o.og|-x) 80 22 keg= [Pch] (ch [pas 0.36 (0.091-x) 2 x² + 0.362 6.03276= 0 solving fro X x=0.0753 (rahia) X=-0.435 (Not valid) SO [Pcb] = = X = 0.0753 80 [Pcb]= 0.0753M