Please answer the following question using the numerical iteration method and show all steps! Thank you!
Please answer the following question using the numerical iteration method and show all steps! Thank you!...
Problem 1 A duct with diameter D, surface roughness e, and length L = 1500 feet transports air with specific weight Yair = 0.0752 lbs/ft at volume flow rate of Q = 9000 ft/min. A pressure gradient of Ap/L is measured in inch of water per 1500 feet of duct. Use either a graphical method (preferred) or a numerical iteration method to fill out the table below. Show all steps. If you choose to use a graphical method, show a...
Please answer this problem using the iteration method where
applicable. Thank you!
Problem 2 Water flows from an upper reservoir to a lower reservoir with an elevation drop of Az = 20m and flow velocity V. The water pipe has a diameter D, surface roughness ε = 0.0002m and length L = 100m. Find the flow velocity for f=0.019. (a) Determine V for D = 20cm and a friction factor f = 0.019. (b) Determine V for D = 20cm...
please show the steps and formula !
#2 in the pipe flow problem, the key flow parameters are Ap pressure drop, p density, Vavg averaged velocity, u viscosity, L pipe length, and D pipe diameter. Use the Buckingham Pi method to determine the number of dimensionless groups and the dimensionless groups. Check those group to show that they are dimensionless.
Solve number 5 a and b showing all steps and units
please
b. Repeat computation of AP/L in psi/ft when flow rate is reduced to 20000 gal/day 5. An elevated storage tank drains by gravity to a vessel a fluid with density 0.72 gr/cm3 and viscosity 0.6 cp through a pipe 200 m length by 0.12 m diameter. Surface roughness of 0.00015ft The vessel is located 15 m below the storage tank, and both are open to the atmosphere a....
Please help with the following matlab code and please show all
work. Thank you!
Viscous losses in a pipe are expressed in terms of a friction factor, f. It is important to know the frictional forces in pipe flow because they result in pressure loss which must be accounted for in the piping system. For turbulent low in pipes, the friction factor is caleulated using the Colebrook e/D 2.51 where e is the roughness height, D is the pipe diameter...
show all steps please! thank you
Problem 2. In the approximation that the Earth is a sphere of uniform density, it can be shown that the gravitational force it exerts on a mass m inside the Earth at a distancer from the center is mg(r/R), where R is the radius of the Earth. Suppose that there is hole drilled along the diameter straight through the Earth and the air was pumped out of the hole. If UPS dropped a package...
Solve by using the SIMPLEX method. Show all steps please. Thank
you!
min s.t. F(x)= 3x, – x2 g(x)=-4x2 + x2 50.5 g(x)= x2 + x2 56 g(x) = 3x, -X, 21 X2,4220 min s.t. F(x)=-3x, +xz g(x) = 0.5x, +xz 56 82(x)=-2x, +x, 2-5 h(x)= 0.5x4 – x2 = 1 ,42 30 min s.t. F(x) = 3x2 + x2 81(x) = 3x2 + x2 23 82(x)= x;/4+xz 21 83(x)=-2x, +xz 52 X1,4, 20
QUESTION!!
ANSWER!!
Please show all steps so I can understand the methods
used to solve it. Thank you!
2. A "very long" strip footing with the width of 4m is placed on the ground surface with a pressure equal to 100 kPa. Calculate the stress distribution at depths of 3 and 6 m below the center of the footing. Use Boussinesq, Westergaard, and 2:1 method for the evaluation. Vertical stress, σ' (kPa) 3m below 6m belovw Boussinesq Westergaard 2:1 method
Please show all steps in solving the problem. Thank you!
8.) Euler's Method Given the following equation: Use Euler's method to estimate the value of y(t) for t = 0.5, 1, 1.5 seconds (At = 0.5). The initial condition is y(0) = 6. Fill in the table below with your results Room for comments 0 0.5
show all steps please
QUESTION ANSWER 970. Ms The rate law for the following reaction is rate - k[HPO40 (H) What is the value of k based on the given data? 1.35 x 10'M's H, PO (aq) + 3 l'(aq) + 2 H(aq) - H,PO (aq) + 1, (aq) + H,00 129 X 10 M Trial [H POJ (M) [1] (M) [H'](M) Initial rate (M/s) 0.150 0.1500.150 0 .220 0.3000 .1500.150 0.440 0.150 0.450 0.150 0.660 0,300 0 .150 0.300...