Question

Please help with the following matlab code and please show all work. Thank you!

Viscous losses in a pipe are expressed in terms of a friction factor, f. It is important to know the frictional forces in pipe flow because they result in pressure loss which must be accounted for in the piping system. For turbulent low in pipes, the friction factor is caleulated using the Colebrook e/D 2.51 where e is the roughness height, D is the pipe diameter and Re is the pipe Reynolds number (dimensionless). For e/D-0.008 and Re-5x 105, solve the equation for f. Use any of the methods discussed in class (except MATLAB-provided functions). Solve until the relative approximation error is S0.0001

Answer 1

The problem is solved using matlab code. For more information, refer to matlab website or drop a comment below. Please give a Thumbs Up, if solution is helpful.

Solution :

Using a general trial regression method, the friction factor f can be found using following matlab code,

clear;

clc;

eD = 0.008; % Relative Roughness

Re = 5e+5; % Reynolds number

f = 0.1;
e = 10;

while e>0.0001
  
LHS = -2*log10((eD/3.4) + (2.5/(Re*sqrt(f))));
  
RHS = 1/sqrt(f);
  
e = abs(LHS - RHS);
  
f = (1/LHS)^2;
  
end

f

e

And the result obtained is,

Command Window 0.0363 6.9749e-06

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