Molar mass of NaOH,
MM = 1*MM(Na) + 1*MM(O) + 1*MM(H)
= 1*22.99 + 1*16.0 + 1*1.008
= 39.998 g/mol
mass(NaOH)= 0.715 g
use:
number of mol of NaOH,
n = mass of NaOH/molar mass of NaOH
=(0.715 g)/(40 g/mol)
= 1.788*10^-2 mol
volume , V = 1.7*10^2 mL
= 0.17 L
use:
Molarity,
M = number of mol / volume in L
= 1.788*10^-2/0.17
= 0.1052 M
So,
[OH-] = 0.1052 M
use:
pOH = -log [OH-]
= -log (0.1052)
= 0.978
use:
PH = 14 - pOH
= 14 - 0.978
= 13.022
Answer: 13.022
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