Question

ACDS AND BASES Calculating the ph of a strong base solution A chemist dissolves 582. mg of pure sodium hydroxide in enough water to make up 100 mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Round your answer to 3 significant decimal places X

Answer 1

Molarity of the solution is given by M = weight of the solute*1000/molecular weight of the solute* volume in mL

Molarity of the solution is given by M = 0.582*1000/40*100 = 0.1455 M

1 mole of NaOH produces 1 mole of OH- ions.

Therefore, the concentration of OH- ions from 0.1455 M is [OH-] = 0.1455 M

pOH = -log[OH-] = -log(0.1455) = 0.83

pH = 14-pOH= 14-0.83 = 13.17 =~ 13.2