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Examn Room P102_Index: Student ID Number: Signature: 4- (25 pts) A paralel-plate capacitor is constructed from efore two square plates of sides L and seperation d. Initially the space between plates contains only air (ε=eo) The capasitor is charged by a batery providing constant voltage Vo. A material of dielectric constant K-7 is inserted into the capacitor as shown in the figure K-7 d/3 L/2 (a) Find the capacitance of the device before and after the dielectric was inserted Vo (b) Calculate the total charge on the capacitor before and after the dielectric was inserted. 2 2 (c) Canculate the enery stored on the capacitor before and after the dielectric was inserted

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Answer #1

I have attached three scanned sheets of solution for this question.

Capacity is calculated using formula 1 for the first case and using formula 2 when slab is inserted. Formula 2 I have used directly but if u want the derivation of the formula then I can produce it.

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Fosmula O le cabac Formula e slab is inserted 4hick ness t heve Area AL Since sqe blakt CalculatinFor a aster inserting slab is can be shown like: combination C and s cmecと。し72 2 よ387 oZd S d Totul chere ushen dielechic is inserted 5 5dEnera stod before slab inset 212 Ene s to red after slab insex ted 2 2 5 d Ua lo d

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