Question

F,-mg 980 m/s-32.2 s dr dt Ve dv dr x-Acos(cot + φ) 2rt tan U-(12)kx object on a spring of constant 45 N/m is undergoing simple harmonic motion. The maximum potential energsy onsider a time when the speed of the object is 5.0 m's. At that time, find is 55 J. C a) the potential energy of the system. b) the acceleration of the object

Answer 1

a)Maximum potenti al energy of the objectis 2U 2(55 J) 45 N/m 1.563m The expression for angular frequency of os cill ati ons is, M2 45N/m 3kg 3.872rad/s The instataneous speed particle of simple harm onic oscillator is Here, A is the amplitude of oscilltion andy is the displacement 2 (5.0m/s) (3.872rad/s) 0.88m Potenti al energy of the system is (45Nm) (0.88m) 17.4 J (b) Acceleration of the object is, - (3.872rad/s) (0.88m) -13.2m/s