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8. Three charges are placed at the corners of a 45-45-90 degree triangle. Let q45 +3.2 X 10-10, q45 +3.2 X 10-10 and q9o +6.4 X 10-10. The legs of the triangle are of length 1 meter. Calculate the magnitude of the electric field at point P, equidistance for each of the charges. (Use GUESS method.) Answer 11.52 N/C
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Answer #1

Here, we will have circumradius of triangle, here the hypotenuse is the diameter of the circle so, distance to each charge is 0.5 m.

E = kq / r2

E = 9e9 * 3.2e-10 / 0.52

E = 11.52 N/C

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