Part A The standard enthalpy of formation for ethanol (CH,COOH() is 484.3 kJ/mol What is the...
6.82. Acetic acid, CH, COOH, is contained in vinegar. Suppose acetic acid was formed from its elements, according to the following equation: 2C(graphite) + 2H2(g) + O2(g) → CH,COOH(1) Find the enthalpy change, AH, for this reaction, using the following data: CH, COOH(D) +20 (9) ► 2007 (9) + 2H2O(); AH = -874 kJ C(graphite) + O2(g) + CO2(g); AH = -394 kJ H2(g) + O2(g) → H2O(l); AH = -286 kJ
5. The standard molar entropy of liquid ethanol (C2H5OH) is 160.7 J K mol and the standard enthalpy of combustion is - 1368 kJ mol at 298 K, how much is the standard Gibbs energy (A,Gº) of formation of liquid ethanol at 298 K? (20 pts) The formation reaction of ethanol is 2C (graphite) + O2(g) + 3H2 (g) → C2H5OH() The combustion reaction of ethanol is CH5OH (1) + 302 (9) ► 200, (g) + 3H20 (1) CO; (g)...
Enthalpy of Formation
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A scientist measures the standard enthalpy change for the following reaction to be 591.0 kJ : 2H2O(1)—>2H2(g) + O2(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(l) is kJ/mol. A scientist measures the standard enthalpy change for the following reaction to be -2903.4 kJ: 2C2H6(g) + 7 O2(g)—>4CO2(g) + 6 H2O(g) Based on this value and the standard...
The standard enthalpy of formation of NH_2(g) id -46 KJ mol^-1.The standard enthalpy of formation of H_2O(g) is -242 KJ middot mol^-1. The enthalpy of reaction is 906 kl. The standard enthalpy of formation of NO(g)is a. -754.5 kJ middot mol^-1 b. -362 kJ middot mol^-1 c. -196.5 kJ middot mol^-1 d. -90.5 k middot J-mol^-1 e. +90.5 kJ middot mol^- 1 f. +182.5 kJ middot mol^-1 g.+317 kJ middot mol^-1 h. +362 kJ middot mol^-1 i. +409 kJ middot...
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite) + 2 H2(g) + 1026) → CH2OH(1) Given the following data: CH2OH() • 02(9) + CO2(g) + 2H2O(1) AH°: -726.4 kJ/mol C(graphite). O2(g) → CO2(9) AH' = -393.5 kJ/mol H2(g) + 40269) → H2O(1) AH = -285.8 kJ/mol
The standard enthalpy of formation of CO(g) is −111 kJ/mol [refer to this equation C(s) + 1/2O2(g) ⟶ CO(g)] What is the ΔHorxn of this reaction? (What is the standard enthalpy change of this reaction?) 2C(s) + O2(g) ⟶ 2CO(g) -253 kJ/mol - 222 kJ/mol -97.1 kJ/mol 534 kJ/mol 124.9 kJ/mol -50.5 kJ/mol 5 points QUESTION 2 (assume A, B, C, and D and E are chemicals) Look at these equations A + B à C ΔH° = -9 kJ/mol rxn...
Generally enthalpy values are given in kJ/mol. However, convert the enthalpy of neutralization value of -110.83 kJ/molNaOH to BTU/gram NaOH. BTU stands for British thermal unit. (Put your answer in 3 significant figures) Given the following information below, use Hess’s Law to calculate the enthalpy of formation for sodium oxide: Na (s) + HCl (l) à NaCl (aq) + ½ H2 (g) ∆HRx = -397.9 kJ/mol Na2O (s) + 2 HCl (l) à 2 NaCl (aq) + H2O ∆HRx = -652.8 kJ/mol H2 (g) + ½ O2 (g) à ...
The standard enthalpy of formation of NaF(s) is -573.6 kJ/mol, and the standard enthalpy of formation of NaF(aq, 1m) is -572.8 kJ/mol. Determine the standard enthalpy of solution of NaF.-0.8 kJ/mol-572.0 kJ/mol+0.8 kJ/mol-1146.4 kJ/mol+1146.4 kJ/mol
What is the standard enthalpy of formation of What is the standard enthalpy of formation of CH 3 CH 2 CH 2 CHO(l)? CH3CH2CH2CHO(l)? 2CH 3 CH 2 CH 2 CHO(l)+5O 2 (g)→8H 2 O(l)+8CO 2 (g); 2CH3CH2CH2CHO(l)+5O2(g)→8H2O(l)+8CO2(g); ΔH°=–4943.6 kJ ΔH°=–4943.6 kJ Substance ΔH° f (kJ/mol) CO 2 (g) -393.5 H 2 O(l) –285.8 a. –245.4 kJ/mol b. +245.4 kJ/mol c. –1792.5 kJ/mol d. –3151.1 kJ/mol e. +3151.1 kJ/mol
The standard enthalpy change for the following reaction is -426 kJ at 298 K. Na(s) + 1/2 O2(g) + 1/2 H2(g) → NaOH(s) AH° = -426 kJ What is the standard enthalpy change for the reaction at 298 K? 2 Na(s) + O2(0)+ H2()—2 NaOH(s) The standard enthalpy change for the following reaction is 484 kJ at 298 K. CH3COOH(1) ► 2 C(s,graphite) + 2 H2(g) + O2(g) AH° = 484 kJ What is the standard enthalpy change for this...