Preferences of men:
= A,B,C,D
= A,B,C,D
= B,C,A,D
= C,A,B,D
Preferences of women:
A = ,,,
B = ,,,
C = ,,,
D = ,,,
What does the algorithm look like? The algorithm is called
"men-proposing algorithm". In each iteration, an unmarried man
proposes to the first woman on his list that he hasn’t proposed to
yet. A woman who receives a proposal that she prefers to her
current assignment accepts it and rejects her current
assignment.
- Now, proposes to the
first woman on his list: A. A has no offers and accepts.
- proposes to A,
who rejects. He moves on to the second woman on his list: B. She
has no offers and accepts.
- Now, proposes to B. B
prefers over and
rejects him. moves on to the
second woman on his list: C. C has no offers and accepts.
- Next, asks out C, who
refuses, because she prefers over .
moves on to the
second woman on his list: A. Now, A prefers to , so
she agrees and rejects .
- moves on to B,
who prefers him to .
- asks out C who
prefers him over , she accepts his
offer and rejects .
- asks out A, who
prefers him over everyone else, she accepts and rejects
.
- asks out B, the
third woman on his list, who prefers him over others, so she
accepts him and rejects .
- asks out C, who
prefers him over everyone else, and she accepts him, rejects
.
- asks out the
final woman on his list, D, who has no offers and accepts.
Hence, we get,
with C
with D
with A
with B
This association meets the definition of a stable marriage
profile.
Hope this helped!
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