Question

A sample of an ideal gas in a cylinder of volume 4.14 L at 298 K and 2.24 atm expands to 7.48 L by two different pathways. Path A is an isothermal, reversible expansion. Path B has two steps. In the first step, the gas is cooled at constant volume to 1.38 atm . In the second step, the gas is heated and allowed to expand against a constant external pressure of 1.38 atm until the final volume is 7.48 L . Calculate the work for path A. Calculate the work for path B.

Answer 1

Path A! Itt say idal gos = 1 moto W = nRT ln v2/11 49L = 1 mbl.x 8-314 584mb1-1 x 290 Klin este = 8987/35/3 = 14651587 212.95 Kly 14. 12, 1.38 com] Path B? (41142, 298, 2.24atr) Cooled ATAS L, +38ch ) In the first step as the proces is constant volune proces so ar=o, . su wao. now offer fint step terpench will be T. anviar, Pilt=P2/12 t2 = P2 x T/P 298k 1.38 alla x > 1. 2.24ab 183,59K Now, in and to step Total ware in both B we P(^2-1) cm 1.Balm ( 7.48L - 4.142) - 4.61 Larm = 4.61 x 101.325) = 467.13 = 46713