Homework Answers
Path A:
Work done in isothermal process = nRT* ln(Vi / Vf), where n is number of moles, Vi is initail volume and Vf is final volume
From ideal gas equation: pV = nRT. Using this we get: w = PV * ln(Vi / Vf)
Using the given values: 2.63 * 2.82 * ln(2.82 / 8.40) = -8.095 lit-atm = -8.095 * 101.325 = -820.23 J
Path B:
Work done = -P * Change in Volume = -1.40 * (8.40 - 2.82) = -7.812 lit-atm = -791.55 J
A sample of an ideal gas in a cylinder of volume 4.14 L at 298 K...
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1.00 mile of a monoatomic ideal gas at 298 K undergoes isothermal expansion from an initial...
1.00 mile of a monoatomic ideal gas at 298 K undergoes
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a) against a constant external pressure
b) reversibly and isothermally.
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Consider an ideal gas enclosed in a 1.00 L container at an internal pressure of 24.0 atm. Calculate the work, w, if the gas expands against a constant external pressure of 1.00 atm to a final volume of 24.0L. Now calculate the work done if this process is carried out in two steps. 1. First, let the gas expand against a constant external pressure of 1.50 atm to a volume of 16.0L. 2. From the end point of step 1,...
1.00 mile of a monoatomic ideal gas at 298 K undergoes
isothermal expansion from an initial pressure of 12.0 bar to 5.00
bar. Calculate the work if the expansion is done
a) against a constant external pressure
b) reversibly and isothermally.
Problem 3 1.00 mole of a monoatomic ideal gas at 298 K undergoes isothermal expansion from an initial pressure of 12.0 bar to 5.00 bar. Calculate the work if the expansion is done (a) against a constant external pressure...
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