Cost of machine = $96,000
Annual benefit = $16,000
Annual maintenance = $4,000
Useful life = 20 years
MARR = 8%
Calculate the NPW -
NPW = -Cost of machine - Annual maintenance(P/A, i, n) + Annual benefit(P/A, i, n)
NPW = -96,000 - 4,000(P/A, 8%, 20) + 16,000(P/A, 8%, 20)
NPW = -96,000 - (4,000 * 9.8181) + (16,000 * 9.8181)
NPW = -96,000 - 39,272.4 + 157,089.6
NPW = 21,817.2
So,
The NPW is closest to $21,816
Hence, the correct answer is the option (D).
C 259, on it! b. A machine is bought with $96,000, Benefit is $16000 and maintenance...
Buy a pump with 10,000, Salvage with 4,000 after 10 years. Yearly maintenance is 500 and benefit 800. At int rate =8%, which the correct formula? Put A, B, C, D A. NPW (Machine X) = 10,000 - 800 (P/A, 8%, 10) - 500 (P/A, 8%, 10) + 4,000 (P/F, 8%, 10) B. NPW (Machine X) = 800 (P/A, 8%, 10) - 500 (P/A, 8%, 10) + 4,000 (F/P, 8%, 10) - 10,000 C. NPW (Machine X) = 300 (P/A,...
according to engineering economy replacment analysis
b- A Canadian company owns a machine that cost $26 000 ten years ago. A new machine is available that costs $11 000 and will save $2000 per year. If the new machine is bought, the old machine can be sold for $8000, and the new machine can itself be sold for $1000 salvage five years hence. If the old machine is retained, it will be scrapped in five years, for no salvage value....
QUESTION 3For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10%Machine AMachine BMachine CFirst cost, $26,5383000010000Annual cost, $/year8,0606,0004,000Salvage value, $4,0005,0001,000Life, years362Answer the below questions:A- AW for machine A=QUESTION 4For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10%Machine AMachine BMachine CFirst cost, $1500021,66710000Annual cost, $/year8,8706,0004,000Salvage value, $4,0005,0001,000Life, years362Answer the below questions:B- AW for machine B=
Please show work on excel
8-18 0ZY, Inc. is evaluating new widget machine offered by three companies. The chosen machi A will be used for 3 years. Company Company Company A $25,000 400 $15,000 1,600 $20,000 900 First cost Maintenance and operating Annual benefit Salvage value 8,000 3,000 13,000 9,000 6.000 4,500 NOTE: MARR used is 15%. Use 4 years instead of 3 years. ("The chosen machine will be used for 4 years.") Solve for the following for each company...
4. For single project, if B/C 1, then we implement the project. True False 5. Consider the following projects: Project A has a cost of 50, uniform annual benefit of 6.1 and salvage value of 37.5; Project B has a cost of 40, uniform annual benefit of 6, and salvage value of 25; Project C has a cost of 30, uniform annual benefit of 4.85, and salvage value 25; Project D has a cost of 25, uniform annual benefit of...
3) (20 pts.) A company bought a machine for $60,000. It was expected to last 5 years and has no salvage value. At the end of the fourth vear the machine is declared obsolete and is donated to a school. What is the loss to the company if the following depreciation method was used? a) Straight Line b) SOYD c) 5-year MACRS d) Double Declining Balance
the
life of the machine is 6 years
s A company bought a machine for $4,000 that has an estimated salvace value of $1,000 at the end o -year useful life. Compute the depreciation schedule and the book value schedule using. a) Double declining balance depreciation (2 pts) 2 (4000) = 1333.3 YEAR DDB Dep 1333-3 888. a 592.6 395.06 2638 Tyth.58 D DB BV 444.43 294.3 197.53 131.66 ² (26667 ) = 888.9 2 (1777.8) = 592.6 3 (1185-2)=395.06...
1. Assume that your private university's tuition is $28,000 a) If inflation rate for the tuition is 5% per year calculate what the tuition will cost 20 years from now? b) If general inflation rate for the economy is 3% per year, express that future tuition 20 years from now in real dollars, based on today's rate. 2. The local gas company has asked the planning department of your company to help them plan for future cash flows. They want...
13. Using benefit-cost ratio analysis, b 5 year useful life, and a 15% MARR, determine which of the following mutually exclusive alternatives should be selected. D 310 380 470 Cost Annual Benefit Salvage/Value Ule OS 8 90
One alternative is to replace 18. Typically, there are two alternatives in a replacement analysis. the defrender now. The other alternative is which of the following? A. Keep the defender for its remaining useful life. B. Keep the defender for another year and then reexamine the situation. Censthe defender until an improved chalenger better than the current challenger comes to market D. Keep the defender as long as it's operational 19. A hospital in The Upper Cumberland area bought a...