Question

A 5.06 L cylinder contains 1.92 mol of gas A and 3.25 mol of gas B, at a temperature of 35.0 °C. Calculate the partial pressu

0 0
Add a comment Improve this question Transcribed image text
Answer #1

1) for Gas A:

Given:

V = 5.06 L

n = 1.92 mol

T = 35.0 oC

= (35.0+273) K

= 308 K

use:

P * V = n*R*T

P * 5.06 L = 1.92 mol* 0.08206 atm.L/mol.K * 308 K

P = 9.5903 atm

= 9.5903*101.33 kPa

= 972 kPa

Answer: 972 kPa

2) for Gas B:

Given:

V = 5.06 L

n = 3.25 mol

T = 35.0 oC

= (35.0+273) K

= 308 K

use:

P * V = n*R*T

P * 5.06 L = 3.25 mol* 0.08206 atm.L/mol.K * 308 K

P = 16.2336 atm

= 16.2336*101.33 kPa

= 1645 kPa

Answer: 1645 kPa

Add a comment
Know the answer?
Add Answer to:
A 5.06 L cylinder contains 1.92 mol of gas A and 3.25 mol of gas B,...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT