6) For the reaction 4 HBr(aq) + O2(g) = 2 Br2(aq) + 2 H2O(l), K. -6.7...
The reaction 4 HBr(g) + O2(g) 2 H2O(g) + 2 Br2(g) was studied at a certain temperature with the following results: Experiment [HBr(g)] (M) [O2(g)] (M) Rate (M/s) 1 0.00579 0.00579 0.365 2 0.00579 0.0116 0.732 3 0.0116 0.00579 0.732 4 0.0116 0.0116 1.47 (a) What is the rate law for this reaction? ______ (b) What is the value of the rate constant? ______ (c) What is the reaction rate when the concentration of HBr(g) is 0.00598 M and that...
13. Consider the reactions below; H2S(g) + H2O(1) H2S(g) + 2H2O(l) H30'(aq) + HS (ag); K1 - 2.5 x 10 + 2H30 (aq) + (aq); K3 = 6.8 x 10-16 Use the information above to calculate the K for the reaction given below (6 points); HS (aq) + H2O(0) H:0 (aq) + (aq); K = ? 14. Consider the reaction below; 2NO2(g) + 2Cl2 2NOCl2(g) + O2(g) If the equilibrium constant Kat 100°C is 1.5 x 10, calculate its k....
Consider the following chemical reaction. NH3(g) + 2 O2(g) → HNO3(aq) + H2O(l) Calculate the change in enthalpy (ΔH) for this reaction, using Hess' law and the enthalpy changes for the reactions given below. (1a) 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l); ΔH = −1166.0 kJ/mol (2a) 2 NO(g) + O2(g) → 2 NO2(g); ΔH = −116.2 kJ/mol (3a) 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g); ΔH = −137.3 kJ/mol
4) The equilibrium constant kc for the reaction H2(g) + Br2(g) = 2HBr(g is 2.18 x 106 at 730°C. Starting with HBr only with (HBr]° = 0.267 M, calculate the concentrations of H2, Brz, and HBr at equilibrium.
The equilibrium constant K. for the reaction H2(g) + Brz(g) = 2HBr(g) is 2.18 x 106 at 730°C. Starting with 3.20 moles of HBr in a 12.0-L reaction vessel, calculate the concentrations of H2, Br2, and HBr at equilibrium. (10 points) (Reference: Chang 14.43
1) Consider the following reaction at equilibrium: H2(g) + Br2(g) = 2 HBr(g) Kc = 3.8 x 104 a) Is this reaction reactant-favored or product-favored? (1 point) Answer: b) Based on the given equilibrium reaction, determine the value of the equilibrium constant for the following reaction: Show your work for full credit! (4 points) 2 HBr(g) = H2(g) + Br2(g) Kc = c) Use both the equation and your answer from Part b to answer the problem. In a 1.00...
At 700 K, Kc = 1.56×10–2 for the reaction 2 HBr(g) ⇌ H2(g) + Br2(g). In a given experiment, 0.050 mol of H2, and 0.050 mol Br2 are introduced into a 5.0-L flask. What is the equilibrium concentration of HBr?
Part A N2(g)+3Br2(g)⇌2NBr3(g) K=[NBr3]2[N2][Br2]3 K=[N2][Br2]3[NBr3]2 K=[NBr3][N2][Br2] K=[NBr3]2[N2][Br2]3 Part B C(s)+O2(g)⇌CO2(g) K=[CO2][O2] K=[O2][CO2] K=[CO2][O2] K=[CO2][O2][C] When heated, carbon reacts with water to produce carbon monoxide and hydrogen. C(s)+H2O(g)+heat⇌CO(g)+H2(g) Part C What effect does each of the following changes have on the equilibrium? Drag the appropriate stresses to their respective bins. add H2O, Add heat, lower temperature, remove CO Categories: Equilibrium shifts to products, Equilibrium shifts to reactants, Equilibrium doesn't shift
please please show the work and explinations! 4. K for the reaction Br2(g) 2Br(g) is 1.1 x 10 reaction at this temperature. at 1280°C. Calculate the value of K, for this (a) 1.1 x 10 (b) 18 (c) 0.14 (d) 910 (e) 8.3 x 10 5. Which of thg following reactions favors reactants? (a) H2(g)+ F2(g) 2HF(g ) K- 1.2 x 10 (b) 2NO(g)+ Cl:(g) 2NOCI (g): K= 4.6 x 10 cN:(g)+ Olg)= 2NO(g)K 4.7 x 1031 (d) 2NO(g) +O:(g)#...
Calculate the equilibrium constant K for the reactions at 298 K. a) Br2(g) + 2Cl-(aq) ---> 2Br-(aq) + Cl2(g) b) A Galvanic Cell with the SHE and Fe+2/Fe(s)