At 700 K, Kc = 1.56×10–2 for the reaction 2 HBr(g) ⇌ H2(g) + Br2(g). In a given experiment, 0.050 mol of H2, and 0.050 mol Br2 are introduced into a 5.0-L flask. What is the equilibrium concentration of HBr?
At 700 K, Kc = 1.56×10–2 for the reaction 2 HBr(g) ⇌ H2(g) + Br2(g). In...
At 700 K, Kc = 1.56-10-2 for the reaction 2 HBr(g) + H2(g) + Br2(c). In a given experiment, 0.050 mol of H2 and 0.050 mol Br2 are introduced into a 5.0-L fiask. What is the equilibrium concentration of HBr? Multiple Choice О оо16 м o O o.250 м o O o125 м o О 31-10-3 м o О 7,8*10-3 м
1) Consider the following reaction at equilibrium: H2(g) + Br2(g) = 2 HBr(g) Kc = 3.8 x 104 a) Is this reaction reactant-favored or product-favored? (1 point) Answer: b) Based on the given equilibrium reaction, determine the value of the equilibrium constant for the following reaction: Show your work for full credit! (4 points) 2 HBr(g) = H2(g) + Br2(g) Kc = c) Use both the equation and your answer from Part b to answer the problem. In a 1.00...
10. The equilibrium constant Kc for the reaction H2(g) + Br2(g) ⇆ 2HBr(g) is 2.180 × 106 at 730°C. Starting with 2.20 moles of HBr in a 13.7−L reaction vessel, calculate the concentrations of H2, Br2, and HBr at equilibrium. [H2] = [Br2] = [HBr] =
The Kc of the reaction H2 (g)+Br2 (g)=2HBr (g) is 2.18×10+6. If the initial concentration of HBr in 12.0L vessel is 3.20 moles, calculate the concentration of H2, Br2 and HBr at equilibrium. Use ICE table. Show calculations and all work & may have to use quadratic equation.
For the reaction: H2+Br2 ⇌ 2HBr, Kc = 7.5x10^2 at a certain temperature. 1.00 mole HBr is placed in 5.0 L flask at a certain temperature. What is the concentration of HBr at equilibrium? a) 0.19 b) 0.81 c) 0.01 d) 0.94 e) 0.03 What I got so far for the molarity, H2 + Br2 ⇌ 2HBr I 0 0 .2 C +x +x -2x (due to 2 moles) E x x .2-x ----------------------------------------------- for kc 7,5x10^2 = 750, put...
A mixture of 1.374 g of H2 and 70.31 g of Br2 is heated in a 2.00 L vessel at 700 K . These substances react as follows: H2(g)+Br2(g)⇌2HBr(g) At equilibrium the vessel is found to contain 0.566 g of H2. 1A) Calculate the equilibrium concentration of H2. 1B) Calculate the equilibrium concentration of Br2. 1C) Calculate the equilibrium concentration of HBr. 1D) Calculate Kc.
For the equilibrium Br2(g)+Cl2(g)⇌2BrCl(g) at 400 K, Kc = 7.0. Part A If 0.25 mol of Br2 and 0.55 mol of Cl2 are introduced into a 3.0-L container at 400 K, what will be the equilibrium concentration of Br2? Express your answer to two significant figures and include the appropriate units. Part B If 0.25 mol of Br2 and 0.55 mol of Cl2 are introduced into a 3.0-L container at 400 K, what will be the equilibrium concentration of Cl2?...
The equilibrium constant Kc for the reaction H2(g) + Br2(g) ⇆ 2HBr(g) is 2.180 × 106 at 730°C. Starting with 1.20 moles of HBr in a 21.3−L reaction vessel, calculate the concentrations of H2, Br2, and HBr at equilibrium.
H2(g)+I2(g)⇌2HI(g) For the above reaction, Kc=55.3 at 700 K. In a 2.00-L flask containing an equilibrium mixture of the three gases, there are 0.053 g of H2 and 4.39 g of I2. What is the mass of HI in the flask?
Be sure to answer all parts. The equilibrium constant Kc for the reaction H2(g) + Br2(g) ⇆ 2HBr(g) is 2.180 × 106 at 730°C. Starting with 2.20 moles of HBr in a 18.1−L reaction vessel, calculate the concentrations of H2, Br2, and HBr at equilibrium. [H2] =___ M Br2] = ___M [HBr] = ____M