1)
Balanced chemical equation is:
HI + NaOH ---> NaI + H2O
Here:
M(HI)=0.113 M
V(HI)=14.4 mL
V(NaOH)=15.7 mL
According to balanced reaction:
1*number of mol of HI =1*number of mol of NaOH
1*M(HI)*V(HI) =1*M(NaOH)*V(NaOH)
1*0.113*14.4 = 1*M(NaOH)*15.7
M(NaOH) = 0.1036 M
Answer: 0.104 M
2)
Balanced chemical equation is:
2 HI + Ba(OH)2 ---> BaI2 + 2 H2O
Here:
M(HI)=0.191 M
V(HI)=25.9 mL
V(Ba(OH)2)=19.1 mL
According to balanced reaction:
1*number of mol of HI =2*number of mol of Ba(OH)2
1*M(HI)*V(HI) =2*M(Ba(OH)2)*V(Ba(OH)2)
1*0.191*25.9 = 2*M(Ba(OH)2)*19.1
M(Ba(OH)2) = 0.1295 M
Answer: 0.130 M
An aqueous solution of sodium hydroxide is standardized by titration with a 0.113 M solution of...
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