H3PO4(aq) + 3 KOH(aq) → K3PO4(aq) + 3 H2O(l).
You mix 750. mL of 0.1250 M H3PO4 with 750. mL of 0.350 M KOH
What is the theoretical yield of water produced - in grams?
H3PO4(aq) + 3 KOH(aq) → K3PO4(aq) + 3 H2O(l). You mix 750. mL of 0.1250 M...
Consider the following reaction: H3PO4 (aq) + 3KOH (aq) --> K3PO4 (aq) + 3H2O(l) You mix 750. mL of .1250 M H3PO4 with 750. mL of .350 M KOH I) Which reactant is limiting? H3PO4 or KOH II) What is the theoretical yield of water produced in grams?
The neutralization of H3PO4 with KOH is exothermic. H3PO4(aq)+3KOH(aq)⟶3H2O(l)+K3PO4(aq)+173.2 kJ If 55.0 mL of 0.207 M H3PO4 is mixed with 55.0 mL of 0.620 M KOH initially at 23.29 °C, predict the final temperature of the solution, assuming its density is 1.13 g/mL and its specific heat is 3.78 J/(g·°C). Assume that the total volume is the sum of the individual volumes. ?final= °C
Complete the following reaction: H3PO4 (aq) + KOH(aq) → H3PO4 (aq) + 3 KOH (aq) + 3 H2O (1) + K3PO4 (aq) H3PO4 (aq) + KOH(aq) → H2 (g) + H20 (1) + KPO4 (aq) 2 H3PO4 (aq) + 3 KOH(aq) + 3 H20 (1) + 2 K3PO4 (aq) H3PO4 (aq) + KOH (aq) → H20 (1) + K3PO4 (aq) H3PO4 (aq) + KOH(aq) → H30 (1) + KPO4 (aq)
The neutralization of HPO with KOH is exothermic 4 Н, РО, (аq) + 3 КОНаq) 3 H2O(l) + K3PO4 (aq) 173.2 kJ If 65.0 mL of 0.220 M H PO4 is mixed with 65.0 mL of 0.660 M KOH initially at 21.49 °C, predict the final temperature of the solution, assuming its density is 1.13 g/mL and its specific heat is 3.78 J/(g.°C). Assume that the total volume is the sum of the individual volumes 333.4 °C Trinal
A solution of 0.230 M KOH is used to titrate 20.0 mL of a 0.168 M H3PO4 solution. What volume, in milliliters, of the KOH solution is required? H3PO4(aq)+3KOH(aq)→3H2O(l)+K3PO4(aq)
1. A student performs a titration that requires 40.00 mL of 0.5000 M KOH to completely react with 30.00 mL of a H3PO4 solution. What is the molarity of the H3PO4 solution, if the two compounds react according to this equation? (HINT: DO NOT use MiV=M2V2 to solve for the molarity of acid involved in a titration!) H3PO4 (aq)+ 3 KOH(aq) → K3PO4 (aq) + 3 H2O(1)
An unknown concentration of phosphoric acid is titrated to its equivalence point with 0.2701 M KOH. What is the concentration of the acid? H3PO4 (aq) + 3 KOH(aq) - K3PO4 (aq) + 3 H2O) Initial volume of KOH solution 1.03 mL Final volume of KOH solution 15.02 mL Original volume of H3PO4 solution 24.68 mL O 0.001260M 0.05104 M 0.1531 M 0.4593M
If a 25.0 mL sample of phosphoric acid, H3PO4, is completely neutralized by 137 mL of 0.100 M KOH, what is the molarity of the phosphoric acid? Given: H3PO4 + 3 KOH → 3 H2O + K3PO4
12.60 milliliters of a 1.25 M KOH solution are required to titrate 20.0 milliliters of a H3PO4 solution. What is the molarity of the H3PO4 solution? 3KOH + H3PO4 --> K3PO4 + 3H2O 0.513 M 2.52 M 0.0550 M 0.728 M 3.04 M 0.263 M 1.45 M 0.817 M Refer to this equation: 3SCl2 + 4NaF --> SF4 + S2Cl2 + 4NaCl 64.0 grams SCl2 is reacted with excess NaF and 12.5 grams of SF4 is formed. What is percent...
HaPO4(aq) + KOH(aq) → KsPOa(ag) + H2O(/) Consider the unbalanced equation above. What is the concentration of the original KOH solution if 81.5 mL of the KOH solution reacts with 2.85 g of H3PO4? AICI(aq) NaOH(ag) → Al(OH)3(s) + NaCl(aa) Consider the unbalanced equation above. What volume of 0.150 M sodium hydroxide is needed to react with 82.5 mL of 0.190 M aluminum chloride? mL CrCls(s) + AgNO3 (aq) → AgCl(s) + Cr(NO3)3(aq) A 0.830 g sample of impure CrCl3...