If a 25.0 mL sample of phosphoric acid, H3PO4, is completely neutralized by 137 mL of 0.100 M KOH, what is the molarity of the phosphoric acid?
Given: H3PO4 + 3 KOH → 3 H2O + K3PO4
If a 25.0 mL sample of phosphoric acid, H3PO4, is completely neutralized by 137 mL of...
18. (5 pts.) A 155.0 mL portion of aqueous phosphoric acid solution was completely neutralized by 45.38 grams of Lithium hydroxide. The chemical equation is: 3 LiOH (s) + H3PO4 (aq) → Li3PO4 (s) + 3 H2O (1) The concentration of the phosphoric acid, in molarity, is: (a) 4.075 M (b) 1.611 M (c) 11.40 M (d) 3.942 M
A 25.00 mL sample of a phosphoric acid solution is completely neutralized using 17.12 mL of 0.13 M sodium hydroxide. What is the initial concentration of phosphoric acid?
a student is preforming a titratio in lab. a sample of phosphoric acid with a volume of 12.05 mL requires 33.21 mL of 0.173 M potassium hydroxide to reach the equivalence point. H3PO4 + 3 KOH = K3PO4 +3 H2O A.) what is the concentration of the phosphoric acid?
18. (5 pts.) A 155.0 mL portion of aqueous phosphoric acid solution was completely neutralized by 45.38 grams of Lithium hydroxide. The chemical equation is: 3 LiQH (s) + H3PO4 (ag) → Li3PO4 (s) + 3 H2O (1) The concentration of the phosphoric acid, in molarity, is: (a) 4.075 M (bude bill M (c) 11.40 M (d) 3.942 M 19.6.5 pts.) At 79.00°F the enthalpy of a reaction was found to be +342.8 KJ/mole and its entropy change was +395.0...
18. (5 pts.) A 155.0 mL portion of aqueous phosphoric acid solution was completely neutralized by 45.38 grams of Lithium hydroxide. The chemical equation is: 3 LiOH (s) + H2PO4 (aq) → Li3PO4() + 3 H20 (1) The concentration of the phosphoric acid, in molarity, is: (a) 4.075 M (b) 1.611 M (C) 11.40 M (d) 3.942 M
18. (5 pts.) A 155.0 mL portion of aqueous phosphoric acid solution was completely neutralized by 45.38 grams of Lithium hydroxide. The chemical equation is: 3 LiOH (s) +H,PO, (aq) a Li,PO, (s) + 3 H20 (1) The concentration of the phosphoric acid, in molarity, is: (a) 4.075 M (b) 1.611 M (c) 11.40 M (d) 3.942 M
1. A student performs a titration that requires 40.00 mL of 0.5000 M KOH to completely react with 30.00 mL of a H3PO4 solution. What is the molarity of the H3PO4 solution, if the two compounds react according to this equation? (HINT: DO NOT use MiV=M2V2 to solve for the molarity of acid involved in a titration!) H3PO4 (aq)+ 3 KOH(aq) → K3PO4 (aq) + 3 H2O(1)
9. a If 25.0 mL of KOH solution is neutralized by 13.31 mL of 0.111 M H3PO4, what is the molarity of the KOH? State formula, of course you were going to do that, right? b) How many mL of 0.123 M H2SO4 solution is needed to neutralize 25,0 mL of 0.250 M KOH solution?
An unknown concentration of phosphoric acid is titrated to its equivalence point with 0.2701 M KOH. What is the concentration of the acid? H3PO4 (aq) + 3 KOH(aq) - K3PO4 (aq) + 3 H2O) Initial volume of KOH solution 1.03 mL Final volume of KOH solution 15.02 mL Original volume of H3PO4 solution 24.68 mL O 0.001260M 0.05104 M 0.1531 M 0.4593M
A 10.00 mL sample of phosphoric acid is titrated with 20.15 mL of a 2.50 mol/L sodium hydroxide solution. H3PO4 (aq) + NaOH ----> H2O (l) + Na3PO4 (aq) a) Balance the molecular equation and write the net ionic equation. b) calculate the molarity of phosphoric acid. c) calculate the mass percent of phosphoric acid in the water mixture (density = 1.50 g/mL)