3.) A 2 kg skier is going up a ski ramp at 15m/s, b but wasn't going fast enough to make it off the jump. a.) If the snow is completely b.) If the snow's coefficient of frictsion is 0.2, how high does the skier get? how high up the ramp do they get? recall, the distance up the ramp will be hisine, and the normal force-mgcoso) 2.) Explain why we often say that energy is lost' when dealing with...
A 90 kg skier at the top of a 400 m icy hill slides down, through a 20 m patch of snow (µk= 0.25) and hits a 20 m long jump ramp at a 45° incline. a) (10 points) How far from the edge of the ramp does the skier land (m)? b) (5 points) How high will he get of the ground (max height (m)) ?
A 90 kg skier at the top of a 400 m icy hill slides down, through a 20 m patch of snow (uk-0.25) and hits a 20 m long jump ramp at a 45° incline. a) (10 points) How far from the edge of the ramp does the skier land (m)? b) (5 points) How high will he get of the ground (max height (m)) ? 400 m 20 m 45° X 20 m
A 90 kg skier at the top of a 400 m icy hill slides down, through a 20 m patch of snow (uk= 0.25) and hits a 20 m long jump ramp at a 45° incline. a) (10 points) How far from the edge of the ramp does the skier land (m)? 400 m 20 m 45° X 20 m b) (5 points) How high will he get of the ground (max height (m)) ?
QUESTION 16 A 90 kg skier at the top of a 400 m icy hill slides down, through a 20 m patch of snow (uk-0.25) and hits a 20 m long jump ramp at a 45° incline. a) (10 points) How far from the edge of the ramp does the skier land (m)? 1400 m 20 m 45° 20 m b) (5 points) How high will he get of the ground (max height (m)) ?
A 90 kg skier at the top of a 400 m icy hill slides down, through a 20 m patch of snow (µk= 0.25) and hits a 20 m long jump ramp at a 45° incline. a) (10 points) How far from the edge of the ramp does the skier land (m)? b) (5 points) How high will he get of the ground (max height (m)) ? Ho 400 m 20 m 45° X 20 m
A skier with mass 64.0 kg starts at rest at the top of an 842 m long ski slope, which makes an angle 13.0 ∘ with the horizontal. A typical coefficient of friction between skis and snow is 5.20×10−2. skiers don't go straight down the hill- they zigzag back and forth. Even though they still end up at the bottom of the hill, they've lost more energy to friction because friction is a non-conservative force. Let's say due to zigzagging,...
In the figure, a T-bar ski tow pulls a skier up a hill inclined at 10.º above horizontal. The skier starts from rest and is pulled by a cable that exerts a tension T at an angle of 30.º above the surface of the hill. The mass of the skier is 60. ke and the effective coefficient of kinetic friction between the skis and the snow is 0.10. 30 (a) Draw the free-body diagram for the skier. (4 pts) 400...
A 55.0 kg skier with an initial speed of 11.0 m/s coasts up a 2.50 m high rise as shown in the following figure. Vi = ? KE 2.5 m / 35° Find her final speed at the top (in m/s), given that the coefficient of friction between her skis and the snow is 0.0800. (Hint: Find the distance traveled up the incline assuming a straight-line path as shown in the figure.) m/s
A 55.0 kg skier with an initial speed of 14.0 m/s coasts up a 2.50 m high rise as shown in Figure 6.23. Find his final speed at the top, given that the coefficient of friction between her skis and the snow is 0.0800. (Hint: Find the distance traveled up the incline assuming a straight-line path as shown in the figure.)