(a) V = V0(1 + *∆T) where is the volume temperature extension coefficient
so,
V = 150 ( 1 + 0.00109 * (21 - 4.8))
V = 152.6487 mL
Therefore, overflow will be
V = 2.6487 mL
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(b) In case of water
V = 150 ( 1 + 0.000214 * 16.2)
V = 150.52002 mL
V = 0.52002 mL
less overflow of water = 2.6487 - 0.52002 = 2.12868 mL
Note that the values of expansion cofficients are taken from text book and may have slight difference from book to book. However, the method is fine.
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