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5. Which of the choices is a possible product of the reaction shown? н CH3 CH3 Н CH3 Н он- A) CH3 Он CH3 CH3 Br CHз Н Н D) |вWhen I drew the hydrogen and bromine to be anti, I  ended up with the methyl groups being trans. Why is the answer B? Please draw out in detail. Thank you!

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Tu rotation CH3 make of H Br Brant i Loo to each Now D4 Br anti other. to each other, H& Br SYN to each other. (they are not

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