Question

ANSWER ALL THE QUESTIONS IF YOU ANSWER FIRST FOUR CERTAINLY I WILL GIVE DISLIKES

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Answer 1

1. The answer will be A . Explanation is given in the image attached.
No. of moles of Oo in A - 2 moles No. of " 1" Hy in B = a moles. A8 B have equal volume. Temp = T (constant) - Pressure in A & B will be same. Al to Avogadro's law equal volo of gases at same temp. & pressure contain awal no. of molecules, Here volume is equal & temp, cond is same. No. of molemles of Og & Hy is also samenso as both are of a moles (i.e.2x 6.093 x 1023 no. of molewki are there), so they must be exerting same pressure.

No. of moles of O in A - 2 moles No. of 1 Hy in B = à moles. A8 B have equal volume. Temp - T Leonstant) - Pressure in A & B will be same. Al to Avogadro's law canal volo of gases at same temp. & pressure contain seveal no. of molecules Here volume is equal & temp, cond is same. No. of molemles of Og & Hy is also samenso a both are of a moles (ie.2x 6.023 x 1023 no. of molewki are there), so they must be exerting same pressure.

2. Answer will be D because all the three hydrogen will first split into a doublet with respect to one hydrogen and then thqt doublet will split into another doublet with respect to the other hydrogen.

3. The correct option will be C because if we take logarithm of the equation given in option A we would finally get option B. So, both the options A and B will be correct.

4. Answer will be A . For the ionic compound AX, charge = 1.6 × 10^-19 coulomb. In gaseous states, ionic compounds are electrically neutral. The solution is given in the image attached.

-31 Dipole moment - Charge & distance b/w two charges. 1- 6x10-19 e X 24681012 m. = 1.6x246x 105 com. 3936 x 183 c.m. = 3.96% 1029 com – 3.94 x 10-29 com. (Ang).

5. Answer is option D i.e. symmetry number of CH₃Cl is 3 because it has three equivalent rotational structures and its point group is C_3v.

6. The correct option will be C because the secondary carbocation first formed on addition of hydrogen will rearrange to more stable tertiary carbocation which will be then attacked by bromide ion to form the final product.

7. The correct option will be A because the ethoxide ion will attack from back as the bromine is at front position. SN2 reaction takes place with inversion of configuration. The carbon bearing methyl group at back position has a hydrogen at front position which is perfectly anti- periplanar to the ethoxide group, so that elimination can take place. For the carbon bearing deuterium at front position , hydrogen atom is present at back position which is not anti- periplanar to ethoxide group. So, elimination is not possible.

8. The correct option will be A because only in water the oxygen atom has two lone pair of electrons which can act as a nucleophile. Methane doesn't have lone pairs or negative charge on it. Borane is electron deficient as it has a vacant orbital, so it would rather act as an electrophile. Ammonium ion has no lone pairs available to donate, rather it has an positive charge on it.

9. The correct option is B. Standard molar entropy is calculated by "product minus reactants". For CHCl₃ , 3 moles of chlorine react with methane, so it has the highest standard molar entropy. For dichloromethane, 2 moles of chlorine are required, so its standard molar entropy is decreased than chloroform. For chloromethane, only one mole of chlorine is required , so it's standard molar entropy is even more decreased.

10. The answer is D. Os is in zero oxidation state and has 8 electrons in its valence orbital. According to neutral electron count method, CO contributes 2 electrons, 2 triphenylphosphine contributes 4 electrons ( 2 electrons each) , chloride ion contributes one electron and the phenyl alkyne group contributes 3 electrons. This gives a total of 8+2+3+4+1 = 18 electrons. For option A, it has 26 electrons. For B, it too has 26 electrons, for C, it has 15 electrons.