1) Aldehyde are more reactive than ketone because ketone contain two alkyl groups which increase electron density on Carbonyl carbon through +I effect thus, Electrophilicity of Carbonyl carbon decreases hence reactivity of ketone towards Nucleophilic addition decreases.
2)
Condensation Reactions Homework (Chapter 19) NAME 1. Explain why aldehyde A is more reactive to nucleophilic...
Condensation Reactions Homework (Chapter 19) NAME 1. Explain why aldehyde A is more reactive to nucleophilic addition reactions than ketone B. В 2. Give the curved arrow mechanism for each aldol reaction. O Он NaOH a. Н.о Н Н ОН NaOH Н.о NaOH, H2O heat Н NaOH, H2O d. heat н"
6. Give the major organic product from each mixed aldol reaction. Then explain why there conditions favor one product instead of generating a mixture of products. NaOH HO H CCI, NaOH HO a. LDA ht 7. Give the curved arrow mechanism for this reaction. he NaOH, H2O heat halla Τ Η 3. Give the major organic aldol product for each reaction, along with the dehydration product possible) formed after heating. NaOH heat H2O heat NaOH H2O ix heat NaOH HO
1. Explain why aldehyde A is more reactive to nucleophilic addition reactions than ketone B.
1. Explain why aldehyde A is more reactive to nucleophilic addition reactions than ketone B.
Identify the electrophilic and nucleophilic carbons. Draw the B-hydroxy product of aldol condensation Draw the dehydration product of aldol condensation CHEMISTRY 204 CONDENSATION REACTIONS WORKSHEET 1. For each of the reactions below: identify electrophilic and nucleophilic carbons draw the B-hydroxy product of aldol condensation . draw the dehydration product of aldol condensation. OH, H2O heat a) CH3CH2CHCH3CH2CH OH, H2O b) CH3CH2CH CH3CH2CH2CH heat еон, H2O heat CH OH, H2O d) heat CH3CH2CH OCH3, CH3OH H, H20 CH3CCH2CH2CH2CCH3 heat CHEMISTRY 204...
3. Give the major organic aldol product for each reaction, along with the dehydration product (if possible) formed after heating. NaOH HO NaOH HO NaOH heat H2O 4. In the following reaction the aldol product C is difficult to isolate, and even without heating the dehydration product D is formed instead. Explain. ОН Ін 10-4 NaOH HO 5. Draw all possible aldol products from this mixed aldol reaction (not dehydrated). NaOH HO
6. Give the major organic product from each mixed aldol reaction. Then explain why the reaction conditions favor one product instead of generating a mixture of products. NaOH a. + Н,о "СС, NaOH b. Н.о a. LDA c. b. О H н 7. Give the curved arrow mechanism for this reaction. NaOH, H,O Н heat
Organic Chemistry 2 Experimental Outline In its simplest form, the aldol condensation is a self-addition involving two molecules of the same aldehyde or ketone, in the presence of a base, and results in the formation of a new carbon-carbon bond joining the carbonyl carbon of one molecule to the a-position of the second. In many cases - if the reaction conditions aren't sufficiently mild - the initially formed aldol product reacts further in an elimination reaction to give what is...
Alpha-Carbon Reactions Homework (Chapter 18) NAME 1. Draw the curved arrow mechanism to show the interconversion of the keto and enol form in either trace acid or base. OH trace OH HO trace H,00 HO OH trace OH HO u mane HO 2. Draw all possible eno tautomers for each molecule (ignoring E/Z stereoisomers).
Give the major organic product of each reaction. 8. a. LDA н b. H c. mild H NaOH, H,O н a, LDA b. f. н NaOH, H,O, heat c. mild H NaOH, H,O O NaOH, H,O H CYD a. LDA b. d. h. NaOH, H,O, heat c. mild H*, heat 9. Give the major organic product of each intramolecular Aldol reaction. NaOH, H,O a. heat H NaOH, H2O b. heat NaOH, H,O NaOH, H20 d. heat 10. Propose starting materials...