Question

Determine the reactions and moments using Three moment equation and draw V, M diagram

SITUATION Ч.A. HI KN 28 kN 38 KN/m rn 21 rn THREE IMOMENT EQUA TION DETERMINE THE REACTIONS, AND MOMENTS, AND DRAW SHEAR AND MOMENT DIAGRAM SOLUTION

Answer 1

Three - moment method A is fixed rightarrow theta_A = 0 D is a binge rightarrow M_oc = 0 B is continuous rightarrow M_BA + M_BC = 0 C is continuous rightarrow M_CB + M_CD = 0 Fixed and moment Because M_FAB = -38 times 3^2/12 - 4.6 times 3^2/30 + 21 times 2/3^2 (3 times 1 - 3) M_FAB = -29.88 KNM Because M_FBA = 38 times 3^2/12 + 4.6 times 3^2/20 + 21 times 1/3^2 (3 times 2 - 3) M_FBA = 37.57 KNM \r\n M_FBC = -42.6 times 4^2/12 + 10.77 times 4^2/30 M_FBC = -28 times 4/8 M_FBC = -76.54 KN/M M_FCB = 42.6 times 4^2/12 + 10.77 times 4^2/20 + 28 times 4/8 = 79.42 KN/M M_FCD = -48.76 times 6^2/12 + - 9.24 times 6^2/30 + -41 times 6/8 M_FCO = -188.12 KN/M M_FDC = 48.76 times 6^2/12 + 9.24 times 6^2/20 + 41 times 6/8 M_FDC = 193.66 KN/M M_AB = -29.88 + 2 times 2 elementof 1/3