Homework Answers
as per gauss law the electric field is integrated over a closed surface is equal to (1/epsilon_not) times of total enclosed charge.
option (c) is correct.
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Item 9 Review Part A Learning Goal: How should the integral in Gauss's law be evaluated?...
Learning Goal: To understand the meaning of the variables in Gauss's law, and the conditions under...
Learning Goal: To understand the meaning of the variables in Gauss's law, and the conditions under which the law is applicable. Gauss's law is usually written ΦE=∮E⃗ ⋅dA⃗ =qenclϵ0, where ϵ0=8.85×10−12C2/(N⋅m2) is the permittivity of vacuum. Part A How should the integral in Gauss's law be evaluated?
To understand the meaning of the variables in Gauss's law, andthe conditions under which the law...
To understand the meaning of the variables in Gauss's law, andthe conditions under which the law is applicable. Gauss's law is usually written where isthe permittivity of vacuum. How should theintegral in Gauss's law be evaluated? around theperimeter of a closed loop over the surfacebounded by a closed loop over a closedsurface
Gauss's law is usually written phi _E = contourintegral E vector middot dA vector = q_encl/epsilon...
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Gauss's law is usually written phi _E = contourintegral E vector middot dA vector = q_encl/epsilon _0 where epsilon _0 = 8.85 times 10^-12 C^2 /(N middot m^2) is the permittivity of vacuum. Correct In the integral for Gauss's law, the vector dA^vector represents an infinitesimal surfa magnitude of dA^vector is the area of the surface element. The direction of dA^vector is no element, pointing out of the enclosed volume. In Gauss's law, to what does q_encl refer? the net...
Learning Goal: To understandAmpère’s law and
its application.
Ampère’s law is often written .
Part A
The integral on the left is
a) theintegral throughout the chosen
volume.
b) the surface integral over
theopen surface.
c) thesurface integral over the closed surface
bounded by theloop.
d) theline
integral along the closed loop.
e) theline
integral from start to finish.
Part C
The circle on the integral means
that must be integrated
a) over
acircle or a sphere.
b) alongany closed...
Learning Goal: To understand Newton's law of gravitation and the distinction between inertial and gravitational masses. In this problem, you will practice using Newton's law of gravitation. According to that law, the magnitude of the gravitational force Fg between two small particles of masses m1 and m2 separated by a distance r, is given by m1m2 T2 where G is the universal gravitational constant, whose numerical value (in SI units) is 6.67 x 10-11 Nm2 kg2 This formula applies not...
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