Question

eir stable state at 25°C and los 4) Calculate AH for the formation on I mole of dinitrogen pentoxide from its elements in their stable state at 25°C and I atm. (The following equations are balanced. N, O, N O 21:) + O2(g) 2H2O(1)-1) AH --571.6 kJ 2 0 - 214. TO, (N:O:( + HOOD - 2HNO (ID))-2 AH -73.7 kJHNO->2NO+2610 NICO) + YOX) + :() -- 2HNOX(I) 49 AH174.1 710L U NO.

Answer 1

dinitrogen pentauxide No Os for formation of Imole of Na Us equation: N2O5 19) Na (9) + 50219) SH = ? SH, = -57116 KJ (1) 2H219) + O219) 2H₂O16) SHIE - on revening in equation, we get (2) 2H₂0 (1) 2H219) + O219) AHO - OH, - - (-571.6) K1 - 571,6 kJ On dividing (2) equation, we get (3) H2018) - H219) & 1 02 19) Ho = SH₂ = 5716 kJ _ 285.6 kJ (41 No Us 191 & ₂ Ultl 2HNO310) Sty= -73.7 RJ On reversing (41 equation, we get (51 2HNO3 (2) N₂O5 lg) + H2Old) AHS - - Sty = - (-7317) KJ = 73.7 kJ (6) No 1g) & 30₂19) & I Haigl - HNO3 (2) AH = -174, 1 KJ On multiply (6) equation, we get (7) Nalg) & 30219) & Halg) - 2HNO3 IR) SHA= 2 x AHI = 2X 1-174. 1) KJ = - 348,2 kJ On adding (3), (5) and (7) equations, we get N219) + 5 0219) - Na Osig ) AH = H₂ + SHS + SH, AH= 285.6 KT + 73.7 KT + (-348.2k5 AH = 11.1 RT. Please Rate