Self-test 3.7 Use standard enthalpies of formation to calculate the enthalpy of combustion of propane gas...
Standard enthalpies of formation are widely available, but we might need a standard enthalpy of combustion instead. The standard enthalpy of formation of ethylbenzene is -12.5 KJ. ,mol. Calculate its standard enthalpy of combustion.
Calculate ΔH∘rxn for this reaction using standard enthalpies of formation. (The standard enthalpy of formation of gaseous propane is -103.9 kJ/mol
Calculate the standard combustion enthalpy of propylene at 25 ° C using the standard formation enthalpy of liquid water (-286 kJ mol-1) and the following reactions: 1) CH2CHCH3 (g) + H2 (g) → CH3CH2CH3 (g); Δ? (1) = -125 kJ mol-1 2) CH3CH2CH3 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (l); Δ? (2) = -2220 kJ mol-1 3) H 2 (g) + 0.5O2 (g) → H2O (l);Δ? ((3) = -286 kJ mol-1
The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ. CzH3(g) + 5 O2(g) + 3 CO2(g) + 4H2O(g) Calculate 4, Hº for propane based on the following standard molar enthalpies of formation. molecule CO2(g) H2O(g) 4,Hº (kJ/mol-rxn) -393.5 -241.8
c Given the following standard molar entropies of formation (S) and enthalpies of combustion to gaseous carbon dioxide and liquid water at 25 °c (AHe AH/kJ mol 393.5 -285.9 -1559.7 C(graphite) H2(g) C2Ho(g) 5.9 131.0 229.5 Calculate the enthalpy change (AH) and Gibbs energy change (AG) for the reaction 2C(graphite) +3H28)CH) datseatt Is this reaction thermodynamically possible? Give a reason for your answer. (10 marks) Explain why it is possible for endothermic processes to occur spontaneously. 15 marks]
Calculate the AH formation of octane, CBH1B (), given that the enthalpy of combustion of octane is -5471 kl/mol and the standard enthalpies of formation of H20 () and CO2 (g) are -393.5 kJ/mol and -285.8 kJ/mol respectively.
8. The standard reaction enthalpy for the hydrogenation of propene, CH-CHCH2 + 5 02 → CH3CH2CH3p. is 124.0 kJ/mol. The standard reaction enthalpy for the formation of water, H ( + 7 O2(g) → H2O).is -286.0 kJ/mole. The standard reaction enthalpy for the combustion of propane, CH3CH2CH3 +5 O2(g) → 3 CO2 + H2O() is 2220 kJ/mol. Calculate the standard enthalpy of reaction for propene. (ANS: -2058 kJ/mol)
Given the enthalpies of combustion of propane (C3Hg), carbon and hydrogen, C3H3(g) + 5 O2(g) + 3 CO2(g) + 4 H20(1) AH° = -2219.9 kJ C(s) + O2(g) + CO2(8) AH° = -393.5 kJ 2 H2(g) + O2 + 2 H2O(1) AH° = -571.6 kJ Calculate the enthalpy of formation of propane. The reaction is shown below. 3 C(s) + 4H2(g) → C3H3(g)
Use Hess’s Law to calculate the heat of combustion of dodecane using heat of formation data. For the calculation you will need the following: Heat of formation data taken from BLBMW Appendix C: fH of formation of carbon dioxide gas is –393.5 kJ/mol, and water (liquid) is –285.83 kJ/mol. and heat of formation of dodeane is -352.1 ± 1.4 kJ/mol
using dimensional analysis
23. The Enthalpy of Combustion, A Hoon of propane, CH, --2,220 kJ/mol. The products of the reaction are carbon dioxide and water. What is the value of AH when 88 g propane is combusted with excess oxygen?