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Consult Multiple-Concept Example 8 for background pertinent to this problem. A 2.00-g bullet, traveling at a...

Consult Multiple-Concept Example 8 for background pertinent to this problem. A 2.00-g bullet, traveling at a speed of 416 m/s, strikes the wooden block of a ballistic pendulum, such as that in Figure 7.14. The block has a mass of 117 g. (a) Find the speed of the bullet/block combination immediately after the collision. (b) How high does the combination rise above its initial position?

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Answer #1

a)

using linear conservation of momentum

m1 u1 = (m1 + m2) v

2* 416 = ( 2+117) v

v = 6.99 m/s

====

b)

using conservation of energy

0.5 M v^2 = M gh

6.99^2/ ( 2*9.8) = h

h = 2.494 m

=======v

do comment in case any doubt will reply for sure.. Goodluck

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