Compute the ratio of the electric force to the gravitational force exerted by a proton on...
The electric force is much stronger than the gravitational force so we can often neglect gravity in electricity and magnetism. How far does the electron of a hydrogen atom have to be removed from the nucleus (contains only one proton) for the force of attraction equal the weight of the electron at the surface of the Earth (g=9.8 m/s2)? Is that large compared to the size of an atom? 2. The electric force is much stronger than the gravitational force...
Also in the hydrogen atom, what is the force exerted by the electron on the proton? If you get the same magnitude for the force as in question 1, could you then conclude (by Newton’s Second Law) that the proton and electron experience the same (centripetal) acceleration magnitude? Why or why not
Compare the electrostatic force between an electron and proton separated by 0.530x10^-10m with the gravitational force between them. This distance is their average separation in a hydrogen atom (r=0.530x10^-10m)
ll. (II) Compare the electric force holding the electron in orbit r 0.53 x 10-10 m) around the proton nucleus of the hydrogen atom, with the gravitational force between the same electron and proton. What is the ratio of these two forces?
5) (2090) The electron is bound to the proton in a hydrogen atom due to the Coulomb force. Now assume that electric charge did not exist and the electron was bound to the proton by the gravitational force to form a hydrogen atom, please derive the corresponding expressions for (a) (8%) the Bohr radius ao and (b) (7%) energy En, (c) (5%) Compute the smallest frequency of the Balmer series. (G-6.67x10 N mKg')
A hydrogen atom is at the earth’s surface. The electron and proton in the atom are separated by a distance of 5.29×10?11m. What is the ratio of the magnitude of the electric force exerted by the proton on the electron to the weight of the electron? r-529 x1σ11 m Mp= 1.67×10 -27 kg /n-911 × 10-31 kg
Determine the magnitude and direction of the electric force on the electron of a hydrogen atom exerted by the single proton that is the atom’s nucleus. Assume the average distance between the revolving electron and a proton is r= 0.53×10^-10m.
3. (a) (6 pts) An electron is orbiting a proton. Find the force between the electron and the proton (b) (8 pts) Find the voltage and the electric field strength this electron sees from the proton (c) (11 pts) in the Bohr model of the hydrogen atom, the electron orbits the proton at the radius of the electron's orbit. Find the current created by the electron orbiting the proton in the Bohr model of the hydrogen atom.
Determine the ratio of the electrostatic force to the gravitational force between a proton and an electron, FE/FG. Note: k = 9.0 x 109 N.m2/C2; G 6.672 x 10-11 N-m2/kg2; 10-31 kg; and m, = 1.672 x 10 27 kg; Qp = 1.6 x 1019 С; Qе me = 9.109 X -1.6 x 1019 C. 1.24 x 1023 1.15 x 1031 1.42 x 1058 2.26 x 1039 2.52 x 1029
For the hydrogen atom from the previous problem, calculate the ratio (F_e/F_g) of the electric force to the gravitational force (m_e = 9.11x10^-31 kg, m_p = 1.67x10^-27 kg). This ratio will show by how much greater the electric force is than the gravitational force (ie, a ratio = 1 would imply the forces are of equal strength).