At the point of fission, a nucleus of 235U that has 92 protons is divided into...
At the point of fission, a nucleus of 235U that has 92 protons is divided into two smaller spheres, each of which has 46 protons and a radius of 5.74 ✕ 10-15 m. What is the magnitude of the repulsive force pushing these two spheres apart? N
Homework Answers
Electrostatic force is given by:
F = k*q1*q2/R^2
k = 9*10^9
q1 = q2 = +46e
e = 1.6*10^-19 C
R = distance between both sphere = 2*r
r = radius of each sphere = 5.74*10^-15 m
R = 2*5.74*10^-15 m
So Using these values:
F = 9*10^9*(46*1.6*10^-19)^2/(2*5.74*10^-15)^2
F = 3699.2 N
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