Question

Spectroscopic data for three organic dyes, A, B, and C, are shown in the table. A solution containing a mixture of the three dyes in a 1.000 cm cuvet had absorbances of 0.3935 at 450 nm, 0.3258 at 480 nm, and 0.6832 at 520 nm. Find the concentrations of the three dyes in the solutions. For each solution, the zero is set with a blank. 1 (nm) en (M-'cm') 450 3200 480 5900 520 27500 €8 (Mcm-) 10900 9400 12200 €c (M-'cm') 19300 1 0100 3500 [A] = [C=C

Answer 1

page:01 Answer: According to the given information, to find the concentration of CA], [8],[c]. Given, absorbance of a solution is sum total of all the individual components. . A = Ait Aa+Az - ec[A] + ec[b] + ec{c} Az ebe with b:lio cm (Pathlength) ea molan absorptivity Co Concencation. - Fºo a, at usonm 0.3935 = 320 0[A] +10900(B] + 19300 (c] al usonm 0-3258 - 5900(m) + quoo[B] +10100[c]

page:02 at sao nm. 06839 - 97500{n} + 12200 [8] + 3800 (c). by solving this three equations, .. we get, Concentrations for [AB =[1:8uxios M [B]= (1 14X105 M] (c] - [1.089X165 M