Question

Spectroscopic data for three organic dyes, A, B, and C, are shown in the table. A solution containing a mixture of the three dyes in a 1.000 cm cuvet had absorbances of 0.4231 at 450 nm, 0.3270 at 480 nm, and 0.5881 at 520 nm. Find the concentrations of the three dyes in the solutions. For each solution, the zero is set with a blank. 1 (nm) 450 480 520 A (M-'cm-) 3200 5900 27500 € (M-'cm- 10900 9400 12200 ec (M-'cm-) 19300 10100 3500 [A] = [C] =

Answer 1

Answers page:01 According to the given information, to find the concentrations of (a), (b), (c). Given, Absorbance of a solution is sum total of all the individual Components. A = Alt Ag+ A3 - eclal z ecſe]+ecc} . Az ebc. with batcm (pathlongth? e. mekan absorptivity c = Concentration. Now; at usonm 0.42 31 = 3000[A] + 10900(B] + 19300 [c] at usonm 0.3270 - 5900 [A] + quoolB] + joloofc}

page: 02 at saonm 05861 - 24500[] + 19200(B] + 3500{c] by using equation, solving three equations we get, Concentrations for (A] lovu xioSM {B} = (1, 21 x 105 Mb [c] = [1, 24 x105 m - o-