Question

Three charges, Q_{1}, Q_{2}, and Q_{3} are located in a straight line. The position of Q_{2} is 0.301 \mathrm{~m} to the right of Q_{1} \cdot Q_{3} is located 0.158 \mathrm{~m} to the right of Q_{2}. The force on Q_{2} due to its interaction with Q_{3} is directed to the.....

False: Left if the two charges have opposite signs.

True: Left if the two charges are positive.

True: Right if the two charges have opposite signs.

False: Right if the two charges are negative.

True: Left if the two charges are neqative.

In the above problem, Q_{1}=1.56 \cdot 10^{-6} \mathrm{C}, \mathrm{Q}_{2}=-3.03 \cdot 10^{-6} \mathrm{C}, and \mathrm{Q}_{3}=3.03 \cdot 10^{-6} \mathrm{C}. Calculate the total force on \mathrm{Q}_{2} . Give with the plus sign for a force directed to the right.

Now the charges \mathrm{Q}_{1}=1.56 \cdot 10^{-6} \mathrm{C} and \mathrm{Q}_{2}=-3.03 \cdot 10^{-6} \mathrm{C} are fixed at their positions, distance 0.301 \mathrm{~m} apart, and the charge \mathrm{Q}_{3}=3.03 \cdot 10^{-6} \mathrm{C} is moved along the straight line. For what position of Q_{3} relative to Q_{1} is the net force on Q_{3} due to Q_{1} and Q_{2} zero? Use the plus sign for Q_{3} to the right of Q_{1}.

Answer 1

please rate it up thanks :)