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A 25.00 mL sample containing an unknown amount of Al3+ and Pb2+ required 17.03 mL of...
Please help! Will rate. A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 56.5...
Please help! Will rate.
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 56.5 mL of 0.0600 M EDTA. Titration of the excess unreacted EDTA required 13.3 mL of 0.0100 M Ca. The Cd2t was displaced from EDTA by the addition of an excess of CN. Titration of the newly freed EDTA required 11.2 mL of 0.0100 M Ca2+. What are the concentrations of Cd2+ and Mn2+ in the original solution? M Mn2+ concentration: M Cd2 concentration: A...
An unknown solution was analyzed for Ni by an EDTA titration. A 50.00 mL sample of...
An unknown solution was analyzed for Ni by an EDTA titration. A 50.00 mL sample of the unknown was treated with 25.00 mL of 0.2404 M EDTA. The excess EDTA was then back titrated with 8.52 mL of 0.0694 M Zn2+ to reach the equivalence point. What was the concentration of Ni (in unit of M) in the 50.00 mL sample? Please keep your answer to three decimal places.
A 24.34 mL aliquot of a Pb2 solution, containing excess Pb2+, was added to 11.50 mL...
A 24.34 mL aliquot of a Pb2 solution, containing excess Pb2+, was added to 11.50 mL of a 2,3-dimercapto-1-propanol (BAL) solution of unknown concentration, forming the 1:1 Pb2+-BAL complex. The excess Pb2+ was titrated with 0.0157 M EDTA, requiring 9.88 mL to reach the equivalence point. Separately, 39.89 mL of the EDTA solution was required to titrate 32.75 mL of the Pb2+ solution. Calculate the BAL concentration, in molarity, of the original 11.50 mL solution concentration:
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of...
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of a 0.04152 M EDTA solution. The solution is then back titrated with 0.02204 M Zn2 solution at a pH of 5. A volume of 16.29 mL of the Zn2+ solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and N solution is fed through an ion-exchange column that retains NP. The Cu2" that passed through the column...
A 1.000-mL aliquot of a solution containing Cu2 and Ni2 is treated with 25.00 mL of...
A 1.000-mL aliquot of a solution containing Cu2 and Ni2 is treated with 25.00 mL of a 0.04328 M EDTA solution. The solution is then back titrated with 0.02246 M Zn2 solution at a pH of 5. A volume of 21.60 mL of the Zn2 solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and Ni2 solution is fed through an ion-exchange column that retains Ni2 . The Cu2 that passed through the...
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 51.7 mL of 0.0500M EDTA....
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 51.7
mL of 0.0500M EDTA. Titration of the excess unreacted EDTA required
15.8 mL of 0.0190 M Ca2+. The Cd2+ was displaced from EDTA by the
addition of an excess of CN−. Titration of the newly freed EDTA
required 13.7 mL of 0.0190 M Ca2+. What are the concentrations of
Cd2+ and Mn2+ in the original solution?
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 51.7...
A 1.000-mL aliquot of a solution containing Cu and Ni2 is treated with 25.00 mL of...
A 1.000-mL aliquot of a solution containing Cu and Ni2 is treated with 25.00 mL of a 0.05182 MEDTA solution. The solution is then back titrated with 0.02198 M Zn2 solution at a pH of 5. A volume of 21.82 mL of the Zn2 solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu and Ni2 solution is fed through an ion-exchange column that retains Ni2. The Cu2 that passed through the column is...
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 57.2 mL of 0.0700 M...
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 57.2 mL of 0.0700 M EDTA. Titration of the excess unreacted EDTA required 14.6 mL of 0.0150 M Ca2+. The Cd2+ was displaced from EDTA by the addition of an excess of CN“. Titration of the newly freed EDTA required 11.3 mL of 0.0150 M Ca2+. What are the concentrations of Cd2+ and Mn2+ in the original solution? concentration: M Mn2+ concentration: M Cd2+
The Fe2+ (55.845 g/mol) content of a 2.264 g steel sample dissolved in 50.00 mL of...
The Fe2+ (55.845 g/mol) content of a 2.264 g steel sample dissolved in 50.00 mL of an acidic solution was determined by tiration with a standardized 0.120 M potassium permanganate (KMnO4, 158.034 g/mol) solution. The titration required 44.82 mL to reach the end point. What is the concentration of iron in the steel sample? Express your answer as grams of Fe per gram of steel Mn2+5 Fe34 H20 + 5 Fe2+ MnO8 H concentration g Fe/g steel A 1.969 g...
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 42.5 mL of 0.0700 M...
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 42.5 mL of 0.0700 M EDTA. Titration of the excess unreacted EDTA required 16.8 mL of 0.0120 M Ca2+. The Cd2+ was displaced from EDTA by the addition of an excess of CN–. Titration of the newly freed EDTA required 26.9 mL of 0.0120 M Ca2+. What were the molarities of Cd2+ and Mn2+ in the original solution? Answer: ([Cd2+] = 0.00646 M; and [Mn2+] = 0.0490 M) The...
Please help! Will rate.
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 56.5 mL of 0.0600 M EDTA. Titration of the excess unreacted EDTA required 13.3 mL of 0.0100 M Ca. The Cd2t was displaced from EDTA by the addition of an excess of CN. Titration of the newly freed EDTA required 11.2 mL of 0.0100 M Ca2+. What are the concentrations of Cd2+ and Mn2+ in the original solution? M Mn2+ concentration: M Cd2 concentration: A...
A 24.34 mL aliquot of a Pb2 solution, containing excess Pb2+, was added to 11.50 mL of a 2,3-dimercapto-1-propanol (BAL) solution of unknown concentration, forming the 1:1 Pb2+-BAL complex. The excess Pb2+ was titrated with 0.0157 M EDTA, requiring 9.88 mL to reach the equivalence point. Separately, 39.89 mL of the EDTA solution was required to titrate 32.75 mL of the Pb2+ solution. Calculate the BAL concentration, in molarity, of the original 11.50 mL solution concentration:
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of a 0.04152 M EDTA solution. The solution is then back titrated with 0.02204 M Zn2 solution at a pH of 5. A volume of 16.29 mL of the Zn2+ solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and N solution is fed through an ion-exchange column that retains NP. The Cu2" that passed through the column...
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 51.7
mL of 0.0500M EDTA. Titration of the excess unreacted EDTA required
15.8 mL of 0.0190 M Ca2+. The Cd2+ was displaced from EDTA by the
addition of an excess of CN−. Titration of the newly freed EDTA
required 13.7 mL of 0.0190 M Ca2+. What are the concentrations of
Cd2+ and Mn2+ in the original solution?
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 51.7...
A 1.000-mL aliquot of a solution containing Cu and Ni2 is treated with 25.00 mL of a 0.05182 MEDTA solution. The solution is then back titrated with 0.02198 M Zn2 solution at a pH of 5. A volume of 21.82 mL of the Zn2 solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu and Ni2 solution is fed through an ion-exchange column that retains Ni2. The Cu2 that passed through the column is...
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 57.2 mL of 0.0700 M EDTA. Titration of the excess unreacted EDTA required 14.6 mL of 0.0150 M Ca2+. The Cd2+ was displaced from EDTA by the addition of an excess of CN“. Titration of the newly freed EDTA required 11.3 mL of 0.0150 M Ca2+. What are the concentrations of Cd2+ and Mn2+ in the original solution? concentration: M Mn2+ concentration: M Cd2+
The Fe2+ (55.845 g/mol) content of a 2.264 g steel sample dissolved in 50.00 mL of an acidic solution was determined by tiration with a standardized 0.120 M potassium permanganate (KMnO4, 158.034 g/mol) solution. The titration required 44.82 mL to reach the end point. What is the concentration of iron in the steel sample? Express your answer as grams of Fe per gram of steel Mn2+5 Fe34 H20 + 5 Fe2+ MnO8 H concentration g Fe/g steel A 1.969 g...
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