A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 51.7
mL of 0.0500M EDTA. Titration of the excess unreacted EDTA required
15.8 mL of 0.0190 M Ca2+. The Cd2+ was displaced from EDTA by the
addition of an excess of CN−. Titration of the newly freed EDTA
required 13.7 mL of 0.0190 M Ca2+. What are the concentrations of
Cd2+ and 
Mn2+ in the original solution?
Homework Answers
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EDTA reacts with metal ions in a 1: 1 mole ratio. That is 1 mole of EDTA reacts with mole of metal ion.
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