Question

1) Given the following orbital parameters, decide what type of orbit it is (elliptical, parabolic, hyperbolic, circular) Orbit parameters a -17839 km e 0.92 Orbit tvpe r-a -6890 km e 1.31 km/s2 0 km2/s2 a 7820 km

Answer 1

For orbital parameters which is given: - a = 17839 km and e = 0.92 since we know that the eccentricity is mainly dependent on the energy of the system such as: - e = squareroot 1 + 2EL^2/mk^2 and also by mathematics we know that: - b^2 = a^2 (1 - e^2) e^2 = 1 - b^2/a^2 e = squareroot 1 - b^2/a^2 then, if e = 1, From the above formula b^2/a^2 = a implies orbit is ''parabola''. and again if e = 0, then, 0 = squareroot 1 - b^2/a^2 b^2/a^2 = 1 implies b^2 = a^2 a = b implies orbit is ''circle'' \r\n similarly, if e > 1, then E > 0 Thus orbit is ''hyperbola''. and if e < 1, then E < 0 Thus orbit is ''ellipse''. Now have the given parameters in (i) and (v) which is: - (i) a = 17839 km e = 0.92 have eccentricity. e < 1 then the orbit is ''ellipse''. (v) Given parameter,
Please describe properly each notation which is given in your question because there are some problem in notation.For rest of the solution please send this question separately with modification.

Sorry for your inconvenience.For any doubt please comment and please give an up vote. Thank you