+q2 +q3 6. Three point charges of g,q+3.7 X 10-19 C and q3+2.2 x 10-19 C...

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Answer 1

Answer #1

here , for the electric field due to charge q1 and q3

length of hypotneuse , h = sqrt(8^2 + 8^2) = 11.314 cm

E1 = k * (q3 - q1)/(h/2)^2

E1 = 9 *10^9 * (3.7 - 2.2)*10^-19/(0.11314/2)^2

E1 = 4.22 *10^-7 N/C

Now, for distance between P and q2

d = sqrt(8^2 + (11.314/2)^2)

d = 9.8 cm

E2 = 9 *10^9 * 3.7 *10^-19/0.098^2

E2 = 3.47 *10^-7 N/C

net electric field = sqrt(4.22^2 + 3.47^2) *10^-7 N/C

the net electric field = 5.46 *10^-7 N/C

the net electric field is 5.46 *10^-7 N/C

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