Question

Please answer in SAS: In an effort to link cold environments with hypertension in humans, a preliminary experiment was conducted to investigate the effect of cold on hypertension in rats. Two random samples of 6 rats each were exposed to different environments. One sample of rats were held in a normal environment at 26°C. The other sample was held in a cold 5°C environment. Blood pressures and heart rates were measured for rats for both groups. The blood pressure for the 12 rats are shown in the accompanying table. Do the data provide sufficient evidence to indicate that rats exposed to a 5°C environment have a higher mean blood pressure than rats exposed to a 26°C environment? Test by using α = .05.

Please note that when I post the question, it seems to not line up 26 degrees and 5 degrees. 5 degrees is rats 7-12.

26 degrees 5 degrees

Rat 1: blood pressure 152 Rat 7: blood pressure 384

Rat 2: blood pressure 157 Rat 8: blood pressure 369

Rat 3: blood pressure 179 Rat 9: blood pressure 354

Rat 4: blood pressure 182 Rat 10: blood pressure 375

Rat 5: blood pressure 176 Rat 11: blood pressure 366

Rat 6: blood pressure 149 Rat 12: blood pressure 423

Answer 1

Null hypothesis: H:44-,50 Alterative hypothesis: H:44-4, > 0 The given level of significance is 0.10. Use the Minitab software to find the test statistic for the given data with the help of following steps: 1. Enter the data in to the Minitab work sheet, 2. Select stat from the Minitab menu bar. 3. Choose stat-> basic statistics->Paired t-test. 4. In the Paired t-test dialog box, click on Each sample is in a column, and shift data 5c in sample 1 and 26 c in sample 2. 3. Choose options ->level of significance (0.05)->alternative hypothesis (5) 6. Click ok.

The obtained output as follows: Paired T-Test and C1: 5c, 26 Paired T for 5 c - 26 C N 5 C 6 26 C Difference 6 6 Mean St Dev SE Mean 378.67 23.86 9.74 166.67 15.73 6.42 212.0 36.7 15.0 951 lower bound for mean difference: 181.8 T-Test of mean difference - 0 (vs > 0): T-Value - 14.15 P-Value - 0.000 From the output, the test statistic value is 14.15 and the p-value is 0.000 Conclusion: Since the p value is less than the significance level, reject the null hypothesis at 5% significance level. Hence, conclude that there is sufficient evidence to indicate that the rats exposed to a 5 c environment have a higher mean blood pressure than rats exposed to a 26 c environment

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