1)
df_grass type = 6-1 = 5
df total = 4*6 -1 =23
SS = MS*df
F = MS grass type /MS Error
ANOVA | ||||
Source of Variation | SS | df | MS | F |
Grass Type | 1000 | 5 | 200 | 1.945945946 |
Error | 1850 | 18 | 102.7777778 | |
Total | 2850 | 23 |
An experiment involved six types of grass and four measurements of density per grass type. Here...
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