show the calculation for the mass of CaCL2 in the unknown mixture please answer both questions.
show the calculation for the mass of CaCL2 in the unknown mixture
please answer both questions.
Homework Answers
Mass of CaCl2 taken = 108.1 - 107.5 = 0.6g
Number of moles of CaCl2 = 0.6g/110.98g/mol = 0.00540638mol
Number of moles of Calcium in Ca3(PO4)2 = number of moles of CaCl2 ÷ 3 = 0.00540638mol /3 =0.00180213mol
Mass of Ca3(PO4)2 ppt formed = 0.00180213mol × 310.177g/mol = 0.55898g (theoretical yield)
% yield =( experimental yield/ theoretical yield )×100 %
= 0.6g/0.55898g × 100% = 107.3 %
= 107.3%
( The yield is greater than 100% means the ppt might not be dried properly . Or there are some error in measuring of mass of ppt).
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show the calculation for the mass of CaCL2 in the unknown
mixture
please answer both questions.
---Percentage of CaCL2 in an unknown mixture Mass of beaker + unknown mixture = 343.103g, Mass...
---Percentage of CaCL2 in an unknown mixture Mass of beaker + unknown mixture = 343.103g, Mass of beaker = 342.235g, Mass of filter paper + Ca3(PO4)2 ppt = 0.682g, mass of filter paper = 0.501g, 1. Show the calculations for the mass of CaCL2 in the unknown mixture. 2. Show the calculations for the percentage of CaCL2 in the unknown mixture.
8. A 0.700-g unknown mixture with CaCl2 reacts with aqueous sodium phosphate to give 0.425 8...
8. A 0.700-g unknown mixture with CaCl2 reacts with aqueous sodium phosphate to give 0.425 8 Ca3(PO4)2. Refer to Example Exercise 15.2 and show the calculation for the percentage CaCl2 in the unknown mixture. DUTY in modo talentos Stan solo longo 9. What safety precautions must be observed in this experiment?
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B. Percentage of NaHCO3 in an Unknown Mixture UNKNOWN # 134 mass of test tube + unknown mixture (before heating) 33,20 34,027 31.48 mass of test tube 31,538 mass of unknown mixture 32,6912 33.283 mass of test tube + residue (after heating) RECYCLE Chemical Waste mass of H2CO3 (H2O + CO2) 8 (before heating - after heating) Show the calculation for the mass of NaHCO3 in the unknown mixture for trial 1 (see Example Exercise 14.2). mass of NaHCO3 g...
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---Percent yield of Ca3(PO4)2 from CaCL2 Mass of beaker + CaCL2 = 342.231g, Mass of beaker...
---Percent yield of Ca3(PO4)2 from CaCL2 Mass of beaker + CaCL2 = 342.231g, Mass of beaker = 341.852g, Mass of filter paper + Ca3(PO4)2 ppt = 0.726, Mass of filter paper = 0.506 1. Show the calculation for theoretical yield of Ca3(PO4)2 2. Show the calculation for percent yield of Ca3(PO4)2
Suppose a 12.42g mixture of NaCl and CaCl2 is dissolved in water. To this solution, an...
Suppose a 12.42g mixture of NaCl and CaCl2 is dissolved in water. To this solution, an excess of AgNO3 solution is added resulting in the formation of 31.12g of the precipitate. Calculate the % by mass of NaCl and CaCl2 in the original mixture. Show all work.
A sample of CaCl2⋅2H2O/K2C2O4⋅H2O solid salt mixture is dissolved in ~100 mL de-ionized H2O. The oven...
A sample of CaCl2⋅2H2O/K2C2O4⋅H2O solid salt mixture is dissolved in ~100 mL de-ionized H2O. The oven dried precipitate has a mass of 0.233 g. The limiting reactant in the salt mixture is K2C2O4⋅H2O. CaCl2⋅2H2O(aq) + K2C2O4⋅H2O(aq) --> CaC2O4⋅H2O(s) + 2KCl(aq) + 2H2O(l) starting material (SM) product Molar Mass (MM) g/mol: CaCl2⋅2H2O = 147.02 K2C2O4⋅H2O = 184.24 CaC2O4 = 128.10 Determine Mass ofK2C2O4⋅H2O(aq) in Salt Mixture in grams. Answer to 3 places after the decimal and include unit, g Do calculation all at once,...
Suppose a 12.42g mixture of NaCl and CaCl2 is dissolved in water. To this solution, an excess of AgNO3 solution is added...
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