Question

PUU DIAS formed as the leaving group is expelled from the a-carbon. This elimination follows Zaitsev's rule whereby the more substituted alkene is generally formed. In E2 elimination, both the B-hydrogen and the leaving group must be oriented anti to each other. The same reaction conditions apply for both Sy2 and E2, therefore these reactions often compete. Use of a strong, hindered base will tend to favor elimination, while use of a weak base/strong nucleophile will favor substitution. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions HH X H₃C/ BrtBuo: - OI HzC CH, tBuoh

Answer 1

Answer e tBuOH Buo CH2 OHese Reaction E2 will take eliminatien Place O A E2 shou ld the leaving rp aaHpeniplannan to the be which will 6e by bulky base AberActed tBnoo et3 H /+Buo tBuOH Hзе CSScanned with CamScanner