Homework Answers
1a) Here, while adding bromocresol green, we got a green colour solution. That indicates that the solution we have taken is in equillibrium with the bromocresol green we added. ie; the pH of solution will be equal to the pH of bromocresol green. unless the solution will become yellow in low pH and blue in high pH. so we can find the pH of solution (which is equal to pH of bromocresol) from Ka value using the equation
-pH = log (Ka)
= log(1.58
10-5
)
-pH= -4.80
pH = 4.80
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A certain indicator, HA, has a Ka value of 2.0 x107. The protonated form of the indicator is blue and the ionized form is yellow What is the pKa of the indicator? Number What is the color of this indicator in a solution with pH 5? O blue O yellow O green
A certain indicator, HA, has a K value of 1.6 x 10^-7. The protonated form of the indicator is blue and the ionized form is yellow. What is the pKa of the indicator? What is the color of this indicator in a solution with pH = 9?
Consider the titration of 25.00 mL of 0.115M NH3 (ka= 5.70e-10 ;
kb= 1.75e-5) with 0.0920 M HCl.
a) calculate the pH of the solution for the following volume of
HCl: 6.25 mL
b) calculate the pH of the solution for the following volume of
HCl: 31.25 mL
c) calculate the pH of the solution for the following volume of
HCl: 50.0 mL
d) Which indicator from the table minimizes the titration error
and why?
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For each of the solutions described below, determine the pH range for the solution using the information given and the indicator chart Solution A Indicator Used alizarin yellow Indicator color Yellow bromthymol blue yellow methyl violet violet Range bear the 21 less than 7.6 leathen lib really them 5.1 Gooher the 3.2 bromcresol green green methyl red red The pH range for solution A is 3.2 7.6 Solution B Indicator Used methyl red Indicator color yellow Range leroth 67 alizarin...
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