Homework Answers
a)
b)
b) The probability that a randomly chosen chip is defective and
from plan B is
P(B and D) = P(B) P(D/B) = 045*001= 00045
c) The probability that randomly chosen chip from PLanc C is defective is P(D/C) = 005
d) The probability that a randomly chosen chip is defective
is
P(D) = P(A and B) + P(B and D) + P(C and D) = 0.009 + 0.0045 +
0.0125 = 0.026
e) Tha probabiltiy a randomly chosen defective chips is from
plant C is
P(C/D) = P(C and D) / P(D) = 0.0125 / 0.026 = 0.481
f) The probability that a randomly chosen chip is not from plant A is P(A') = 1 - P(A) = 1- 0.30 = 0.70
g) The probability that a randomly chosen defective chip is from
plant A is
P(A/D) = P(A and D) / P(D) = 0.009/0.026 = 0.3462
The probability that a randomly chosen defective chip is not from
plant A is
P(A'/D) = 1 - P(A/D) = 1 - 0.3462 = 0.654
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